1) if L has a negative slope. the line will tilt a little backwards. so if (r,s) is above x-axis then intercept > r. if (r,s) is below x-axis then intercept < r. since two ways are possible. not sufficient.sud21 wrote:Point (r,s) lies on the line L. Is the line's intercept with axis-x greater than r?
1). L has a negative slope.
2). s<0
2) s<0. it doesnt give much information. as we dont know the line's slope. it is insuff.
using both,
L has -ve slope and s<0. => the point lies below the x-axis and the line will tilt a little backwards => r > x-intercept. hence sufficient.
user123321
