BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Bus trip - PS

Expert replies
by karthikpandian19 » Thu Dec 15, 2011 11:41 pm
A bus trip of 450 miles would have
taken 1 hour less if the average speed S
for the trip had been greater by 5 miles
per hour. What was the average speed S,
in miles per hour, for the trip?
(A) 10
(B) 40
(C) 45
(D) 50
(E) 55
Join the discussion
Source: — Problem Solving |

by ankush123251 » Thu Dec 15, 2011 11:49 pm
Many methods to solve this but the most algebraic one is:
D= S * t

Let s be average speed and t be the initial time without any increase in speed.
So,
450 = S * T

Then,from the given information,

450 = (S+5) * (T-1)
Solve for S from both equations we have S = 45.

Hope this helps....
You can see options and solve directly also by trying the options.For this always start with option E and backwards.
Join the discussion

by ankush123251 » Thu Dec 15, 2011 11:50 pm
Many methods to solve this but the most algebraic one is:
D= S * t

Let s be average speed and t be the initial time without any increase in speed.
So,
450 = S * T

Then,from the given information,

450 = (S+5) * (T-1)
Solve for S from both equations we have S = 45.

Hope this helps....
You can see options and solve directly also by trying the options.For this always start with option E and backwards.
Join the discussion

by karthikpandian19 » Fri Dec 16, 2011 12:07 am
Thanks,

Is there any other method other than Algebra?
ankush123251 wrote:Many methods to solve this but the most algebraic one is:
D= S * t

Let s be average speed and t be the initial time without any increase in speed.
So,
450 = S * T

Then,from the given information,

450 = (S+5) * (T-1)
Solve for S from both equations we have S = 45.

Hope this helps....
You can see options and solve directly also by trying the options.For this always start with option E and backwards.
Join the discussion

by ankush123251 » Fri Dec 16, 2011 12:36 am
As i said try out the options directly and if you are lucky you can get the answer in 20 seconds!!!
Join the discussion

by ankush123251 » Fri Dec 16, 2011 12:36 am
As i said try out the options directly and if you are lucky you can get the answer in 20 seconds!!!
Join the discussion