BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Probability Question from GMATPrep CAT

Expert replies
by i_have_no_cool_username » Sat Nov 19, 2011 5:30 pm
A certain jar contains only b black marbles, w white marbles, and r red marbles. If one marble is chosen at random from the jar, is the probability that the marble chosen will be red greater than the probability that the marble chosen will be white?

(1) r/(b+w) > w/(b+r)
(2) b-w > r

Answer is A. Why?

Prompt help appreciated, my test is less than 48 hours away!

Thank you, all.
Join the discussion
Source: — Data Sufficiency |

by GMATGuruNY » Sat Nov 19, 2011 6:35 pm
i_have_no_cool_username wrote:A certain jar contains only b black marbles, w white marbles, and r red marbles. If one marble is chosen at random from the jar, is the probability that the marble chosen will be red greater than the probability that the marble chosen will be white?

(1) r/(b+w) > w/(b+r)
(2) b-w > r

Answer is A. Why?

Prompt help appreciated, my test is less than 48 hours away!

Thank you, all.
Like many other DS problems, the one above is most quickly solved by using a little common sense. I posted an explanation here:

https://www.beatthegmat.com/probability-t74040.html
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by mehrasa » Sun Nov 20, 2011 11:50 am
if u want to calculate it algebraically
the Q ask whether p(r)>p(w) we know that p(r)= r/r+w+b and p(w)=w/w+b+r

stat1) r/b+w>w/b+r
first we reciprocate the fractions then the inequality sign flip ==> b+w/r<b+r/w ==> we can add i to both statement but wisely we add r/r to first side and w/w to the second side ===> b+w+r/r<b+r+w/w ==> now again reciprocate and the sign also flip ==> r/b+w+r > w/b+w+r
seems familiar ?! ya we found what we were looking for ==> sufficient
answer is A
Join the discussion

by pemdas » Sun Nov 20, 2011 12:24 pm
wow, such a plethora of reciprocals and changes in sign, why?
mehrasa wrote:if u want to calculate it algebraically
the Q ask whether p(r)>p(w) we know that p(r)= r/r+w+b and p(w)=w/w+b+r

stat1) r/b+w>w/b+r
first we reciprocate the fractions then the inequality sign flip ==> b+w/r<b+r/w ==> we can add i to both statement but wisely we add r/r to first side and w/w to the second side ===> b+w+r/r<b+r+w/w ==> now again reciprocate and the sign also flip ==> r/b+w+r > w/b+w+r
seems familiar ?! ya we found what we were looking for ==> sufficient
answer is A
p(r)>p(w)? OR r/(r+b+w) > w/(r+b+w)? OR r>w?
st(1) r(b+r)>w(b+w) here we have 'b' on both sides of the inequality, so this suggests r>w Sufficient
st(2) r<b-w we know only r<b and nothing about w <,>,= r Not Sufficient.

a
i_have_no_cool_username wrote:A certain jar contains only b black marbles, w white marbles, and r red marbles. If one marble is chosen at random from the jar, is the probability that the marble chosen will be red greater than the probability that the marble chosen will be white?

(1) r/(b+w) > w/(b+r)
(2) b-w > r
Success doesn't come overnight!
Join the discussion