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by GmatKiss » Fri Oct 28, 2011 1:30 pm
If [243^(9 + 18z)](81^-18z)[27^(15 - 9^z)] = 1, what is the value of z?

A) -27
B) -10
C) 0
D) 10
E) 27
Source: — Problem Solving |

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by user123321 » Fri Oct 28, 2011 4:12 pm
GmatKiss wrote:If [243^(9 + 18z)](81^-18z)[27^(15 - 9^z)] = 1, what is the value of z?

A) -27
B) -10
C) 0
D) 10
E) 27
(a^m)^n = a^(mn)

using this if you bring all those bases into same base then you should be able to solve it.
should be 10

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by shankar.ashwin » Fri Oct 28, 2011 9:32 pm
The equation is 3^(something) = 1

You should know you got to equate something = 0.

Writing in base 3;

3^(45 + 90z) * 3^(-72z) * 3^(45 - 27z)) = 1

3^(90-9z) = 1

90=9z
z=10