VIC problem!

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VIC problem!

by Ahmed MS » Sat Oct 22, 2011 4:18 am
Q: If a, b and c are greater than 0 and 'a' is twice as large as 'b' percent of 'c', then in terms of 'b' and 'c', what is 'a' percent of 'c'?

A. 2bc / 100
B. 2bc^2/1000
C. bc^2/5000
D. b^2c/5000


The answer is given C. Can anyone explain how?

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by Anurag@Gurome » Sat Oct 22, 2011 4:26 am
Ahmed MS wrote:Q: If a, b and c are greater than 0 and 'a' is twice as large as 'b' percent of 'c', then in terms of 'b' and 'c', what is 'a' percent of 'c'?
a = 2*(b% of c) = 2*(bc/100) = bc/50

a% of c = ac/100 = a*(c/100) = (bc/50)*(c/100) = bc²/5000

The correct answer is C.
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by krishnakumar.ks » Sat Oct 22, 2011 4:28 am
1. b% of c is (b*c)/100. Since 5% of x is (b*x)/100.

Given a is twice b% of c. Therefore a = 2*(b*x)/100 = b*c/50

Now, a% of c = a*c/100. Same as (1).

Substituting the value of a we have obtained above we get (b*c/50)*(c/100). Hence C.

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by Ahmed MS » Sat Oct 22, 2011 5:23 am
Thanks a lot guys for your help!