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Source: — Data Sufficiency |
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by knight247 » Mon Sep 19, 2011 5:14 am
1) (a+b)² < (a-b)²
Just expand the brackets
a²+2ab+b²<a²-2ab+b²
4ab<0
ab<0 SUFFICIENT
2)a=b both have the same magnitude and sign. So whether both are negative or both are positive a*b>0
SUFFICIENT
D
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by shankar.ashwin » Mon Sep 19, 2011 5:20 am
Me did the same..

OA is A, possibility that a=b=0 in 2nd statement.

Really get pissed doing these mistakes time and again.
knight247 wrote:1) (a+b)² < (a-b)²
Just expand the brackets
a²+2ab+b²<a²-2ab+b²
4ab<0
ab<0 SUFFICIENT
2)a=b both have the same magnitude and sign. So whether both are negative or both are positive a*b>0
SUFFICIENT
D
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