Complicated Absolutes!

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by cans » Sun Sep 18, 2011 9:56 pm
|x| + |y| = 32.
A) -4x-12y = 0 or x+3y=0.
x=-3y.
thus |x|+|y| = |3y| + |y| = 4|y|=32 or |y|=8
xy = -3yy = -3y^2 = -3*64 = -192 Sufficient
B) |x| - |Y| =16.
|x|=24 and |y| = 8
|xy| = 192
But xy can be negative or positive. Insufficient
IMO A
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by Geva@EconomistGMAT » Sun Sep 18, 2011 10:04 pm
Juggernaut_86 wrote:If x and y are non-zero integers and |x| + |y| = 32, what is xy?

(1) -4x - 12y = 0

(2) |x| - |y| = 16


OA after some discussion..

Thanks!
Cool question. The answer is A.

Stat. (1) tells us that x=-3y. Plug this into the equation in the stem:
|-3y| + |y| = 32.

Look at two things separately: sign and value.

Value-wise, y must equal to 8, as 32 = 4*8.
Sign wise, either y=8 or y=-8 will satisfy this equation:
y=8 --> |-24|+|8| = 24+8 = 32
y=-8 --> |-3*-8| + |-8| = |24| + |-8| = 24+8 = 32.

x also has two possible corresponding values from x=-3y:

if y=8, x=-24
if y=-8, x=24

So we haven't limited x and y to a single individual value (actually to two sets of values), but the value of xy will remain the same at -8*24. This is because x and y have opposite signs, so the product will remain negative regardless of which set of value we choose. Stat. (1) - sufficient.

Stat. (2): |x| = |y|+16. Plug this into the equation in the stem:

|x| + |y| = |y|+16 + |y| = 2|y| + 16 = 32.
2|y| = 16
|y| = 8.

Again, this allows y to equal 8 or -8. What about x?

If y=8, then |x| = |8|+16 = 24
If y=-8, then |x| = |-8|+16 = 24

So we get that |x| is equal to 24 - which could still mean that x is equal to +/- 24.

And that's the main difference between (1) and (2): both indicate that y and x are +/- 8 and +/- 24 respectively, but stat. (1) add the additional information for opposite signs, while stat. (2) allows x and y to have opposite signs (e.g. 8 and -24) OR the same sign (e.g. 8 and 24). Thus, the product xy could equal -8*24 or + 8*24 - two possible values. Insufficient.
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