Inequality again

[knight247]

Is ax>bx?
(1)a>b
(2)a+x>b+x

Don't have an OA. Detailed explanations would be appreciated.

[kmittal82]

Is ax > bx
Or, rephrasing

Is x(a-b) > 0
This true under 2 conditions:

x>0 AND a>b
OR
x<0 AND a<b

In either case, we need both the value of x and the relationship between a and b to determine the answer to the inequality

(1)
Tells us a>b, but nothing about x, not sufficient

(2)
Same as (1), i.e. a>b

Combining (1) and (2) is pointless, since both give the same result

Hence, I think its (E)

[top_business_2011]

Is ax>bx?
(1)a>b
(2)a+x>b+x

Don't have an OA. Detailed explanations would be appreciated.

Required: ax>bx?

= ax-bx>0
= x(a-b)>0
The above inequality is valid under the following conditions: When X>0 and a-b>0, which implies a>b, or when x<o and a-b<0. So the question is basically to see whether the statements satisfy any of these conditions.

Statement 1: only a>b, without giving any idea about X. So Insufficient.
Statement 2: a+x>b+x = a+x-b-x>0 =a-b>0 = a>b. This statement gives a different version of the first statement. Hence Insufficient.

Both: No additional info., as both statements are equivalent.

Hence, the answer is E.