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square roots

Expert replies
by GmatKiss » Tue Aug 16, 2011 1:10 pm
If square roots of numbers are considered positive and sqrt(a)+sqrt(b) = sqrt(c)+sqrt(d)+sqrt(e), then is a < c?

(1) c = d
(2) sqrt (b )+ sqrt (d )< sqrt ( e)
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Source: — Data Sufficiency |

by Brent@GMATPrepNow » Tue Aug 16, 2011 6:12 pm
GmatKiss wrote:If square roots of numbers are considered positive and sqrt(a)+sqrt(b) = sqrt(c)+sqrt(d)+sqrt(e), then is a < c?

(1) c = d
(2) sqrt (b )+ sqrt (d )< sqrt ( e)
Nice question.

Aside: Since sqrt(a)+sqrt(b) = sqrt(c)+sqrt(d)+sqrt(e), we know that a, b, c, d and e are each greater than or equal to zero, otherwise we could not have a valid equation involving square roots of negative numbers.

Statement 1: c = d
When we replace d with c in the given equation, we get: sqrt(a)+sqrt(b) = sqrt(c)+sqrt(c)+sqrt(e)
We can simplify this as sqrt(a)+sqrt(b) = 2sqrt(c)+sqrt(e)
From here, can we determine whether or not a < c? No.
Given the equation, sqrt(a)+sqrt(b) = 2sqrt(c)+sqrt(e), we can come up with 2 conflicting cases:
case a: a=b=c=e=0 in which case a is not less than c
case b: a=0, b=4, c=1 and e=0, in which case a is less than c
Since we cannot determine whether or not a < c, statement 1 is not sufficient.

Statement 2: sqrt (b )+ sqrt (d )< sqrt ( e)
For statement 2, I'm going to rewrite the target question.
First, we know that if a < c then it must be true that sqrt(a)< sqrt(c) [as long as a and c are not negative]
So, we can rewrite the target question as: Is sqrt(a)< sqrt(c)?

Better yet, we can use the fact that if x < y, then y - x > 0 to take the rewritten target question, (Is sqrt(a)< sqrt(c)?) and rewrite it as Is sqrt(c)- sqrt(a) > 0?
In other words, Is sqrt(c)- sqrt(a) positive?

Now let's take the given equation:
sqrt(a) + sqrt(b) = sqrt(c) + sqrt(d)+ sqrt(e) and subtract sqrt(a), sqrt(d) and sqrt(e), from both sides to get:
sqrt(b) - sqrt(d)- sqrt(e) = sqrt(c)- sqrt(a) [notice that the right-hand-side matches the new target question]

At this point, we'll take statement 2 and play around with it
We're given that sqrt(b)+ sqrt(d)< sqrt(e)
If we subtract sqrt(e) from both side, we get sqrt(b)+ sqrt(d) - sqrt(e) < 0
In other words, sqrt(b)+ sqrt(d) - sqrt(e) is negative

Important point: if sqrt(b)+ sqrt(d) - sqrt(e) is negative, we can further conclude that sqrt(b) - sqrt(d) - sqrt(e) must be negative as well [since changing +sqrt(d) to -sqrt(d), will make the value of the expression even smaller].

At this point, we're almost done.
We just showed that sqrt(b)- sqrt(d) - sqrt(e) must be negative
And we already know that sqrt(b) - sqrt(d)- sqrt(e) = sqrt(c)- sqrt(a)

From here, we can conclude that sqrt(c)- sqrt(a) must be negative.
Now, our new target question asks Is sqrt(c)- sqrt(a) positive?
Well, we know that sqrt(c)- sqrt(a) is definitely negative, which means we can answer our new target question with certainty (the answer to the target question is "no")

As such, statement 2 is sufficient and the answer is B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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