Is integer N even?

[one of many]

Is integer N even?
1) NxN=N
2)N=N^3

[kmittal82]

(1)
nxn = n
n(n - 1 ) = 0

This means either n=0, or n = 1. Not sufficient

(2)
n - (n^3) = 0
n(1 - n^2) = 0
n(1-n)(1+n)=0

This means n=0, or n=1 or n = -1. Not sufficient

Combining (1) and (2), we get either n=0 or n=1, again, not sufficient

So (E)

Note: I'm considering 0 to be an even number here, i.e. 0 divided by 2 leaves a remainder of 0

[Spartacus2000]

Should zero always be considered an even no.?

Does that apply for all questions eg: Set X contains even nos. < 10, in that case can zero be considered a part of this set?

[Frankenstein]

Should zero always be considered an even no.?

Does that apply for all questions eg: Set X contains even nos. < 10, in that case can zero be considered a part of this set?

Hi,
Yes...Zero is always even.
If set X contains even numbers less than 10, you should consider zero as well. But, if set X contains positive even numbers less than 10, then you shouldn't consider zero because zero is neither positive nor negative.

[kmittal82]

Should zero always be considered an even no.?

Does that apply for all questions eg: Set X contains even nos. < 10, in that case can zero be considered a part of this set?

I believe so. No matter what the test, it shouldn't change the fundamental definition of what is an even number, i.e. a number when divided by 2 leaving no remainder. 0 certainly fits this.