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Number properties question

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
Expert replies
Source: — Quantitative Reasoning |

by sukh » Thu Jul 14, 2011 9:25 am
Thanx and i didnt see the edit button first
Last edited by sukh on Thu Jul 14, 2011 9:43 am, edited 1 time in total.
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by sukh » Thu Jul 14, 2011 9:26 am
the four digit no is divisible by 36 not 4 , i tried to solved by 36= 6*6 i.e. divisble by 2 and 3
but didnt get the point how to solve equations , can You plz explain it again with 36
Last edited by sukh on Thu Jul 14, 2011 9:45 am, edited 1 time in total.
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by Frankenstein » Thu Jul 14, 2011 9:35 am
Hi,
You could have just edited your opening post. You don't to post 3 posts for a single question.
X10X - For a number to be divisible by 4, the last two digits should be divisible by 4
that is 0X is divisible by 4
So, X can be either 4 or 8
For a number to be divisible by 9, the sum of digits should be multiple of 9.
So, x+1+0+x = 2x+1 is divisible by 9
for x=4, 2x+1 = 9
for x=8, 2x+1 = 17(not divisible by 9)
Hence, C
Actually, the options here are in such a way that when you arrive know that 0x should be divisible by 4, you can straight away pick C
Cheers!

Things are not what they appear to be... nor are they otherwise
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by Frankenstein » Thu Jul 14, 2011 10:05 am
sukh wrote:the four digit no is divisible by 36 not 4 , i tried to solved by 36= 6*6 i.e. divisble by 2 and 3
but didnt get the point how to solve equations , can You plz explain it again with 36
Hi,
I have explained it for 36 only. If the number is divisible by 36. It has to be divisible by both 4 and 9.
Cheers!

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by sukh » Thu Jul 14, 2011 10:36 am
Thanx a lot , got the point
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