Area sum

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The Orloff Candy Company packs its cylindrical candy treats in a rectangular container. The height of the container is exactly equal to the height of each treat. How many treats can be packed into each container?

(1) The circumference of the treat is 2 inches.

(2) The area of a horizontal cross-section of the container is 100 inches.


According to me the answer is C. As the height of the cylinder and the height of the rectangular container is the same, then the formula would be:

= (L X B)/(Pie X r^2
if i m wrong please explain...



OA is E.....
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[Frankenstein]

Hi,
1)You are ignoring the vacant space between cylinders. So, you cannot get the number by dividing areas.
2)We need to know the dimensions of the box in order to calculated the number of cylinders that can be fit.
For example:
if the diameter of circle is 4 units and the area is 100 units
If the dimensions of box is 25x4, 25 cylinders will fit.
If the dimensions of box is 10x10, only 20 cylinders will fit.

[goalevan]

It's easiest to think in extremes for this type of problem since no integer constraints are given.

1) The length and width of the box are not given. The box could be a mile wide or 2cm wide. Insufficient.

2) The size of the candies is not given. Their diameter could be 10 centimeters or 10 miles. Insufficient.

Combined) With a square base, the box would be 10 x 10 and could fit some quantity of candies. With a length of 0.00001, not even one candy would fit into the package. Insufficient.

FYI: if you wanted to calculate the number of candies that would fit into a square base, it would go as follows:

C = 2*pi*r = 2, so r = 1/pi and d = 2/pi

We could partition the box into 10 /(2/pi) = 5pi, or 15 rows (rounding down to nearest integer from ~15.7) and 15 columns. The number of partitions and thus candies would be 15 * 15 = 225.