BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Area, Members of Club, Candy Manufacturer

Expert replies
Source: — Problem Solving |

by Anurag@Gurome » Thu Jun 16, 2011 8:52 pm
Please try to do the following when you're posting questions in this forum...
  • 1. Do not post more than one question in the same thread.
    2. Please take the burden of typing the question instead of posting a screenshot. The forum is not for your benefit only. Make the post searchable.
Thanks.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Join the discussion

by Anurag@Gurome » Thu Jun 16, 2011 8:58 pm
PS 1:
A certain candy manufacturer reduced the weight of candy bar M by 20 percent but left the price unchanged. what was the resulting percent increase in the price per ounce of the candy bar M?
Say, initially the weight of each candy was W pounce and price of each candy was P.
Hence, initial price per ounce of each candy = P/W

After reducing the weight, weight of each candy bar = (W - 20% of W) = 0.8*W
After reducing the weight, price per ounce of each candy bar = P/0.8*W = 5P/4W

Hence, increase in price per ounce of each candy bar = (5P/4W - P/W) = P/4W
Hence, percentage increase in price per ounce of each candy bar = 100*(P/4W)/(P/W) = 100/4 = 25%

The correct answer is E.
Last edited by Anurag@Gurome on Thu Jun 16, 2011 9:19 pm, edited 1 time in total.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Join the discussion

by Anurag@Gurome » Thu Jun 16, 2011 9:05 pm
PS 2:
Two members of a club are to be selected to represent the club at a national meeting. if there are 190 different possible selections of the 2 members, how many members does the club have?
Say, there are n members.
Then number of different possible selections of the 2 members out of n = nC2

So, nC2 = 190
--> n!/[(n - 2)!*2!] = 190
--> n(n - 1)/2 = 190
--> n(n - 1) = 380

Now we can solve this quadratic for n or we can look for a two-factor factorization of 380 so that the factors are consecutive integer.

As 380 can be expressed as 19*20, n = 20

The correct answer is A.
Last edited by Anurag@Gurome on Thu Jun 16, 2011 9:20 pm, edited 1 time in total.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Join the discussion

by Anurag@Gurome » Thu Jun 16, 2011 9:13 pm
PS 3:
In the figures above, if the area of the triangle on the right is twice the area of the triangle on the left, then in terms of s, S =
As the triangles are similar, the ratio of their area will be equal to the ratio of the square of their corresponding sides.

So, s²/S² = 1/2
--> S² = 2s²
--> S = √2s

The correct answer is C.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Join the discussion

by qduong » Thu Jun 16, 2011 10:18 pm
Anurag@Gurome wrote:Please try to do the following when you're posting questions in this forum...
  • 1. Do not post more than one question in the same thread.
    2. Please take the burden of typing the question instead of posting a screenshot. The forum is not for your benefit only. Make the post searchable.
Thanks.
Thank you for the suggestion. I didn't know we could "Search" for the problems and now I do.
As for the problems that needed help, I'll type them out so others can search, unless the problems include graphs, figures, or complicated signs.

Thanks
Join the discussion