On July 1 of last year, the total number of employees ...

[qduong]

Two more problems that need explanation. Thank you .

[EddieU]

for the second question (no.8) is the answer 24:25?

[MBA.Aspirant]

2)

Perimeter of square = perimeter of rectangle

4s = 2l+2w

ratio of rectangle sides are 3:2 so assume l=6 and w =4

4s = 2*6 + 2*4
4s = 12+8

s= 5

Area of rectangle : area of square
6*4 : 5*5
24:25

[MBA.Aspirant]

1)

Assume total employees before the drop was 100

after drop = 100*0.9 = 90

Assume salary before the decrease was 50, after increase = 50 * 1.1 = 55

Total salary before drop = 100 *50 = 5000

Total salary after drop = 55 * 90 = 4950

% of salary after drop of before = 4950/5000 = 99%

[winniethepooh]

Let there be 100 employees before July 1 last year.
Therefore, after July 1 employees = 100 - 10(10 % 0f 100)
= 90(remaining employees)

Let the salary of all the employees before July 1 be 100
Therefore, the average of the salaries before July 1 last year will be 1.

But, after July 1 last year the average is said to be 10 % more = 1 + 0.1(10% of 1)
= 1.1(new average salary)

Therefore, the salary after July 1 last year = Remaining employees x new average salary
= 90 x 1.1
= 99

Therefore, the percentage of salary after July 1 last year to the salary before July 1 last year
=99/100 x 100
=99 %.
Hence, B.!