m=6k+2;dell2 wrote:The positive integers m and n leave remainders of 2 and 3,respectively,when divided by 6. m > n.
What is the remainder when m-n is divisible by 6 ?
A-1
B-2
C-3
D-4
E-5
PLEASE SOLVE HOW
THANKS
n=6t+3;
k,t (1,2,3 are +ve integers..)
since m>n; one way is to solve it by substituting values, put k=2 and t=1; we have m=14 and n=9;
m-n=5 hence remainder is 5; by substituting different values of k and t remainder we will find that remainder is always 5,, to understand why its coming 5 all the time we need to be familiar with the concept of -ve remainder,,,!!! if you know it.. then implement it.. if you don't send me a PM i'll explain it to you...!!!
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