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Geometry

by davo45 » Sat Jun 04, 2011 3:44 am
In the figure attached, the area of ABC is 6. BC is 1/3 length of AB, AC =
a:sqrt(2)
b: 2
c: 4
d: 6
e: sqrt(10)
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by MBA.Aspirant » Sat Jun 04, 2011 4:08 am
BC = 1/3 AB

Area of triangle ABC= 1/2 base * height = 6
= 1/2 * 1/3 AB * AB =6
= 1/3 AB^2 = 12
AB^2 = 36
AB = 6

BC = 1/3 AB = 1/3 * 6 = 2

AC = square root AB^ + BC^2

= square root 6^2 + 2^2
= square root 40
= 2 square root 10

Answer is E
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by cans » Sat Jun 04, 2011 9:04 am
area = 6.
(1/2)*AB*BC=6
ab*ab/3 = 12 -> ab^2 = 36
bc^2 = (ab/3)^2 = 36/9 = 4
ac^2 = ab^2 + bc^2 = 36+4 = 40
ac = 2*root(10)
None of the options is correct ( e is mentioned as root(10) only)
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Cans!!
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by cans » Sat Jun 04, 2011 9:04 am
area = 6.
(1/2)*AB*BC=6
ab*ab/3 = 12 -> ab^2 = 36
bc^2 = (ab/3)^2 = 36/9 = 4
ac^2 = ab^2 + bc^2 = 36+4 = 40
ac = 2*root(10)
None of the options is correct ( e is mentioned as root(10) only)
If my post helped you- let me know by pushing the thanks button ;)

Contact me about long distance tutoring!
[email protected]

Cans!!
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by aftableo2006 » Sun Jun 05, 2011 11:31 pm
the answer is 2root10
typo error in the options
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by itsmebharat » Mon Jun 06, 2011 2:02 am
IMO E ,

I guess typo error while writing on the forum..
I am not an Expert, please feel free to suggest if there is an error.
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