mariapazos wrote:Mary, Jhon and Karen are eating lunch together. Karen's meal costs 50% more than Jhon's meal and Mary's costs 5/6 as much as Karen's meal. If Mary pays $2 more tha Jhon, how much is the total that the three of them have to pay?
A. $28.33
B. $30.00
C. $35.00
D. $37.50
E. $40.00
Even someone who struggles with algebra can solve this problem by
guessing and checking.
Let M=Mary, J=John, K=Karen.
Since M = (5/6)K, there is a good chance that M is a multiple of 5 and that K is a multiple of 6.
Let M=10.
Since M pays $2 more than J, J=8.
Since K is 50% more than J, K=12.
Does M=(5/6)K? Yes, because 10=(5/6)12.
Thus, we have found the correct values of M,J and K.
Total = M+J+K = 10+8+12 = 30.
The correct answer is
B.
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