BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Overlapping Sets

Expert replies
by naveenhv » Fri May 06, 2011 9:37 am
Of the 200 members of a certain association, each member who speaks German also speaks English, and 70 of the members speak only Spanish. If no member speaks
all three languages, how many of the members speak two of the three languages?

1) 60 of the members speak only English

2) 20 of the members do not speak any of the three languages.
Join the discussion
Source: — Data Sufficiency |

by force5 » Fri May 06, 2011 12:30 pm
IMO- c

A and B are insufficient.
combining.

total 180
German and english-= x
English and spanish= ES
German and spanish= GS

English only = 60
spanish only = 70
hence 180= 2languages+130
2 languages = 50

hence C
Join the discussion

by Stendulkar » Fri May 06, 2011 1:04 pm
S = Only Spanish
E = Only English
G = Only german

a = spanish + german
b = german + english
c = spanish + english

d = all three

We have to find a + b + c

From information given in the question stem, S = 70, d = 0,G = 0 and a= 0 ( because it is given that everyone who speaks german has to speak english so noone speaks only german and no one speaks german and spanish)

So now we have : S + E + G + a + b + c + d = Students who speak atleast one language.

Therefore, 70 + E + b + c + = Students who speak atleast one language..... (i)

Statement 1 : E = 60

Hoever we do not know how many do not speak any language. There we cannot solve (i)

Statement 2 : RHS of (i) is given but no other info...therefore insufficient.

Combining :

70 + 60 + B + C = 180

B+ C = 50...Sufficient..

This method looks lengthy....but if u use Venn Diagram it becomes very easy..
Join the discussion

by Stendulkar » Fri May 06, 2011 1:05 pm
S = Only Spanish
E = Only English
G = Only german

a = spanish + german
b = german + english
c = spanish + english

d = all three

We have to find a + b + c

From information given in the question stem, S = 70, d = 0,G = 0 and a= 0 ( because it is given that everyone who speaks german has to speak english so noone speaks only german and no one speaks german and spanish)

So now we have : S + E + G + a + b + c + d = Students who speak atleast one language.

Therefore, 70 + E + b + c + = Students who speak atleast one language..... (i)

Statement 1 : E = 60

Hoever we do not know how many do not speak any language. There we cannot solve (i)

Statement 2 : RHS of (i) is given but no other info...therefore insufficient.

Combining :

70 + 60 + B + C = 180

B+ C = 50...Sufficient..

This method looks lengthy....but if u use Venn Diagram it becomes very easy..
Join the discussion

by atulmangal » Fri May 06, 2011 8:41 pm
naveenhv wrote:Of the 200 members of a certain association, each member who speaks German also speaks English, and 70 of the members speak only Spanish. If no member speaks
all three languages, how many of the members speak two of the three languages?

1) 60 of the members speak only English

2) 20 of the members do not speak any of the three languages.
+1 for C

No need to over think..

we need combination of 2 languages, straight away check the possible combinations and infavourable quantities

G + E ---> fav
E + S ---> fav
E only---> Not Fav
NO lang ---> Not fav

so need to find NOT FAV to get the fav combo...Op A and Op B gives that together hence Op C
Join the discussion

by champmag » Sat May 07, 2011 6:47 am
Yes the question becomes very simple with the use of venn diagram.

+1 for C.
Join the discussion