tonebeeze wrote:At a picnic, each of the guests was served either a single scoop or double scoop of ice cream. How many of the guests were served a double scoop of ice cream?
1. At the picnic, 60 percent of the guests were served a double scoop of ice cream.
2. A total of 120 scoops of ice cream were served to all the guests at the picnic.
.
Anurag's approach is great for anyone comfortable with the algebra. Please note, however, that the equation for statement 2 should be S + 2D = 120:
Total number of scoops = 120.
S = number of scoops served to the single-scoop guests.
2D = number of scoops served to the double-scoop guests.
Thus, S + 2D = 120.
Here's an approach that bypasses the algebra:
Statement 1: 60 percent of the guests were served a double scoop.
Plug in a number in order to determine what fraction of the scoops were served to the double-scoop guests.
Let guests = 10.
Then .6*10 = 6 guests were served a double scoop, 10-6 = 4 guests were served a single scoop.
The number of scoops served to the 6 double-scoop guests = 2*6 = 12, the number of scoops served to the 4 single-scoop guests = 1*4 = 4.
Total scoops = 12+4 = 16.
Thus, the double-scoop guests were served 12/16 = 3/4 of the scoops.
No way to determine the number of double-scoop guests.
Insufficient.
Statement 2: A total of 120 scoops were served.
No way to determine the number of double-scoop guests.
Insufficient.
Statements 1 and 2 combined:
The double-scoops guests were served 3/4 * 120 = 90 scoops.
Since each double-scoop guest was served 2 scoops, the number of double-scoop guests = 90/2 = 45.
Sufficient.
The correct answer is
C.
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