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percents

Expert replies
by alltimeacheiver » Thu May 05, 2011 12:36 am
A small pool filled only with water will require an additional 300 gallons of water in order to filled 80 percent of its capacity. If pumping in these additional 300 gallons will increase the amount of water in the pool by 30 percent, what is total capacity of the pool in gallons?

a 1000
b 1250

c 1300
d 1600
e 1625


ques the market value of certain x item decreased by 30 percent each year . If the machine purchased for 8000. what is market value after 2 years later?

a 8000
b 5600
c 3200
d 2400
e 800

I am not getting ans within options
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Source: — Problem Solving |

by Anurag@Gurome » Thu May 05, 2011 1:22 am
A small pool filled only with water will require an additional 300 gallons of water in order to filled 80 percent of its capacity. If pumping in these additional 300 gallons will increase the amount of water in the pool by 30 percent, what is total capacity of the pool in gallons?

a 1000
b 1250
c 1300
d 1600
e 1625


Let us assume that initially the pool is filled with x gallons of water.
x + 300 = 80% of pool's capacity
It is given that pumping in 300 gallons will increase the amount of water in the pool by 30%, which implies 30% of x = 300 implies x = 1000
So, 1000 + 300 = 1300 = 80% of pool's capacity
So, the total capacity of pool in gallons = 1300/80% = 1300/0.80 = 1,625

The correct answer is e.
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by Anurag@Gurome » Thu May 05, 2011 1:31 am
The market value of certain x item decreased by 30 percent each year . If the machine purchased for 8000. what is market value after 2 years later?

a 8000
b 5600
c 3200
d 2400
e 800


Though, it is not a properly worded question, I am assuming that "certain x item" is the machine.
Original price of machine = 8000
Now, the market value of machine decreases by 30% each year implies its price after 1 year = 8000 - (0.30 * 8000) = 8000 * 0.70 = 5600
Market price after 2 years = 5600 - (0.30 * 5600) = 5600 * 0.70 = 3,920
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