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by diebeatsthegmat » Sat Apr 16, 2011 12:43 am
If two numbers are selected from 1,2,3,4 and 5 with replacement, what is the probability that product of two numbers is less than 10 ?

A. 4/5
B. 9/16
C. 16/25
D. 9/25
E. 3/5
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by manpsingh87 » Sat Apr 16, 2011 12:57 am
diebeatsthegmat wrote:If two numbers are selected from 1,2,3,4 and 5 with replacement, what is the probability that product of two numbers is less than 10 ?

A. 4/5
B. 9/16
C. 16/25
D. 9/25
E. 3/5
no. of ways of selecting first number without restriction =5, no. of ways of selecting selecting second number without restriction=5,

now product will be less than 10 if the numbers selected were following
(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4)(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)..!!!

hence required probability would be=15/25=3/5..!!! hence E
Last edited by manpsingh87 on Sat Apr 16, 2011 4:14 am, edited 1 time in total.
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by force5 » Sat Apr 16, 2011 3:08 am
15/25 = 3/5 IMO-E
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