is m + z > 0 ?
(1) m - 3z > 0
(2) 4z - m > 0
Clearly each statement alone is not sufficient!!!
and together we get : 3z < m < 4z
so if z = -2 then m + z < 0
if z = 2 then m + z > 0
I don't understand how it can't be OA E ???
Gmat prep not happy with OA !
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This is a tricky question.mazwaz wrote:is m + z > 0 ?
(1) m - 3z > 0
(2) 4z - m > 0
Clearly each statement alone is not sufficient!!!
and together we get : 3z < m < 4z
so if z = -2 then m + z < 0
if z = 2 then m + z > 0
I don't understand how it can't be OA E ???
Let's start with your (very correct) conclusion that 3z < m < 4z
Notice that we can use this to conclude that 3z < 4z
From here, if we subtract 3z from both sides, we get 0 < z
In other words, z is positive.
If z is positive, then 3z is positive, and since 3z < m, we know that m is positive.
If z and m are both positive, then m+x > 0, so the answer is C.
Aside: notice that z cannot equal -2 (as you suggested) since that would contradict the fact that 3z < 4z
Cheers,
Brent
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Add the two statements: m-3z+4z-m >0 => z > 0
Now using m-3z>0 => m > 3Z => m is +ve, z is positive
thus m+z is +ve... IMO C
Now using m-3z>0 => m > 3Z => m is +ve, z is positive
thus m+z is +ve... IMO C
First take: 640 (50M, 27V) - RC needs 300% improvement
Second take: coming soon..
Regards,
HSPA.
Second take: coming soon..
Regards,
HSPA.