BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Tricky one- Got stumped

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Master | Next Rank: 500 Posts
Posts: 261
Joined: Wed Mar 31, 2010 8:37 pmFollowed by: 3 members
Location: Varanasi
Thanked: 11 times
by ankur.agrawal » Tue Mar 22, 2011 9:16 am
Set S contains seven distinct integers. The median of set S is the integer m, and all values in set S are equal to or less than 2m. What is the highest possible average (arithmetic mean) of all values in set S ?

m

10m/7

10m/7 - 9/7

5m/7 + 3/7

5m
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 1101
Joined: Fri Jan 28, 2011 7:26 amFollowed by: 13 members
Thanked: 47 times
GMAT Score:640

by HSPA » Tue Mar 22, 2011 9:23 am
I got C
the seven numbers i took are
m-3, m-2, m-1, m, 2m-2,2m-1,2m


10m/7 - 9/7... what is the OA
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 857
Joined: Wed Aug 25, 2010 1:36 amFollowed by: 15 members
Thanked: 56 times

by AIM GMAT » Tue Mar 22, 2011 9:30 am
IMO C.

Max number = 2m

median = m

[m-3 , m-2 , m-1 , m , 2m-2 , 2m-1 , 2m ]

sum of all 7 numbers = 10m - 9
mean = (10m - 9 )/ 7
Thanks & Regards,
AIM GMAT
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 586
Joined: Tue Jan 19, 2010 4:38 amFollowed by: 5 members
Thanked: 31 times
GMAT Score:730

by rohu27 » Tue Mar 22, 2011 9:31 am
may i knw the source?

ankur.agrawal wrote:Set S contains seven distinct integers. The median of set S is the integer m, and all values in set S are equal to or less than 2m. What is the highest possible average (arithmetic mean) of all values in set S ?

m

10m/7

10m/7 - 9/7

5m/7 + 3/7

5m
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 857
Joined: Wed Aug 25, 2010 1:36 amFollowed by: 15 members
Thanked: 56 times

by AIM GMAT » Tue Mar 22, 2011 9:37 am
What is the highest possible average (arithmetic mean) of all values in set S ?

[m-3 , m-2 , m-1 , m , 2m-2 , 2m-1 , 2m ]



If it would have been lowest possible then i guess the below mentioned whud be the numbers :-

[m-3 , m-2 , m-1 , m , m+1 , m+2 , 2m ]

sum = 8m - 3
mean = (8m-3)/7

Guys let me know if my approach is wrong.
Thanks & Regards,
AIM GMAT
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1101
Joined: Fri Jan 28, 2011 7:26 amFollowed by: 13 members
Thanked: 47 times
GMAT Score:640

by HSPA » Tue Mar 22, 2011 9:42 am
what if the first element is (m-12345), m-1,m,m+1...blah balh

how did you come to lowest possible conclusion... havent understood AIM
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 857
Joined: Wed Aug 25, 2010 1:36 amFollowed by: 15 members
Thanked: 56 times

by AIM GMAT » Tue Mar 22, 2011 9:52 am
HSPA wrote:what if the first element is (m-12345), m-1,m,m+1...blah balh

how did you come to lowest possible conclusion... havent understood AIM
For highest avg we need to maximize sum so the terms tht are gonna make diff are 5th and 6th terms.

1st : 2nd : 3rd : 4th : 5th : 6th : 7th


m-3 : m-2 : m-1: m :2m-2 : 2m-1 : 2m ---- To maximize sum

m-3 : m-2 : m-1: m :m+1 : m+2 : 2m ---- To minimize sum

Hope that helps.
Thanks & Regards,
AIM GMAT
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Tue Mar 22, 2011 9:57 am
ankur.agrawal wrote:Set S contains seven distinct integers. The median of set S is the integer m, and all values in set S are equal to or less than 2m. What is the highest possible average (arithmetic mean) of all values in set S ?

m

10m/7

10m/7 - 9/7

5m/7 + 3/7

5m
Make the situation concrete by plugging in a value for m.

Let m=5.

For the median to be 5, we need to choose 3 distinct integers that are smaller than 5 and 3 distinct integers that are larger than 5. Since we're trying to maximize the average, we want each integer to be as large as possible.

The largest allowed value is 2m = 2*5 = 10. So the 3 largest integers must be 8, 9, 10.
For the 3 distinct integers smaller than 5, the largest possible are 2, 3, 4.
So our 7 integers are 2, 3, 4, 5, 8, 9, 10.
Average = (2 + 3 + 4 + 5 + 8 + 9 + 10)/7 = 41/7. This is our target.

Now we plug m=5 into all the answers to which yields our target of 41/7.

Only answer choice C works:
10m/7 - 9/7 = (10*5)/7 - 9/7 = 50/7 - 9/7 = 41/7.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 261
Joined: Wed Mar 31, 2010 8:37 pmFollowed by: 3 members
Location: Varanasi
Thanked: 11 times

by ankur.agrawal » Tue Mar 22, 2011 10:19 am
may i knw the source?

Hi rohu,

The Source is MGMAT CAT 1 . Any specific reasons for asking about the source?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 261
Joined: Wed Mar 31, 2010 8:37 pmFollowed by: 3 members
Location: Varanasi
Thanked: 11 times

by ankur.agrawal » Tue Mar 22, 2011 10:21 am
HSPA wrote:I got C
the seven numbers i took are
m-3, m-2, m-1, m, 2m-2,2m-1,2m


10m/7 - 9/7... what is the OA
OA is C. You nailed it.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 586
Joined: Tue Jan 19, 2010 4:38 amFollowed by: 5 members
Thanked: 31 times
GMAT Score:730

by rohu27 » Tue Mar 22, 2011 5:34 pm
yes ankur. i somehow felt it must be from the MGMAT CAT as i did get a similar sort of question.
can i reuqst u to mention the source, especially whn u r posting qustions from CAT's as many of us would not have taken them and reading it before hand would do us no good. hope u dnt mind.

ankur.agrawal wrote:
may i knw the source?

Hi rohu,

The Source is MGMAT CAT 1 . Any specific reasons for asking about the source?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 261
Joined: Wed Mar 31, 2010 8:37 pmFollowed by: 3 members
Location: Varanasi
Thanked: 11 times

by ankur.agrawal » Wed Mar 23, 2011 8:05 pm
can i reuqst u to mention the source, especially whn u r posting qustions from CAT's as many of us would not have taken them and reading it before hand would do us no good. hope u dnt mind.
I am extremely sorry for being so careless. I would take care of this from now. Thanks rohu.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 586
Joined: Tue Jan 19, 2010 4:38 amFollowed by: 5 members
Thanked: 31 times
GMAT Score:730

by rohu27 » Wed Mar 23, 2011 8:20 pm
no need for an apology buddy.glad tht u liked my suggestion :)
ankur.agrawal wrote:
can i reuqst u to mention the source, especially whn u r posting qustions from CAT's as many of us would not have taken them and reading it before hand would do us no good. hope u dnt mind.
I am extremely sorry for being so careless. I would take care of this from now. Thanks rohu.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1