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Circle and square

Expert replies
by DarkKnight » Sat Mar 19, 2011 7:54 pm
Will the circle with centre O fit inside the square ABCE?

1). The diameter of the circle is less than a side of the square
2). The area of the circle is less than the area of square

I am lost at the second statement. Thanks for your help. Answer after few responses.
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Source: — Data Sufficiency |

by vineeshp » Sat Mar 19, 2011 9:56 pm
Answer A?

Second statement says the area of the circle is less than that of the square.

Consider a circle with radius 7 and hence diameter 14 that fits exactly in a square of side 14. The four sides of the square will touch the circle.

Area of the square is 14*14 = 196.
Area of the Circle is Pi*(square of radius) = 154 (Using pi = 22/7.)
Area of circle is less than that of square.

So take another circle of radius 7.7 (using a multiple of 7 for ease of calculation)
Now this circle if centred on the square will go outside the square a bit.
Area of circle wil be 186.34 which is less than the square, yet the circle does not fit inside the square.

So with given information, we got two cases of one circle inside and one circle outside the square.

Hence 2 is not sufficicent.

Statement 1 is straightforward. If the circle's diameter itself is less, then it will be inside the square.
Vineesh,
Just telling you what I know and think. I am not the expert. :)
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by GMATGuruNY » Sun Mar 20, 2011 12:55 am
DarkKnight wrote:Will the circle with centre O fit inside the square ABCE?

1). The diameter of the circle is less than a side of the square
2). The area of the circle is less than the area of square

I am lost at the second statement. Thanks for your help. Answer after few responses.
Let d = diameter of the circle with center O.
Let s = side of square ABCE.

If d ≤ s, then the circle will fit inside the square.

Statement 1: d < s.
Sufficient.

Statement 2: area of circle < area of square.
If s = 20, then the area of the square = 20*20 = 400.
If d = 20, then r = 10, and the area of the circle = π(10^2) = 100π ≈ 300.
Area of the circle < area of the square, and the circle will fit inside the square, since d = s.

If d = 22, then r = 11, and the area of the circle = π(11^2) = 121π ≈ 363.
Area of the circle < area of the square, but the circle will not fit inside the square, since d > s.
Insufficient.

The correct answer is A.
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by DarkKnight » Sun Mar 20, 2011 4:56 pm
Thanks GMATGuru. The OA is A.
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