GMAT Prep Q - p&q

[tito1545]

A step by step approach to this please ?


Are positive integers p and q both grater than n ?

1) p-q is grater than n

2)q>p

[tomada]

For Statement 1, consider the following:

A) p=10, q=6, n=3 => p-q > n and p, q are each > n
B) p=10, q=4, n=5 => p-q > n but only p > n

Statement 1 is insufficient.

For Statement 2, "q>p" gives no information about 'n'.

Statement 2 is insufficient.


Combining statements...

Given that p and q are both positive integers, p-q < 0.
From Statement 1, p-q > n, so n < 0.
Since n < 0 and p > 0 and q > 0, we know that p and q are both greater than n.

Answer: C

[Night reader]

given: p,q (integers) > 0 Are p,q>n ?
st(1) p-q>n means that p>n+q; since q is +ve integer, p>n+ (+ve integer) means that p>n. What about q? q<p-n, we don't know exactly if q>n, it could be both cases - e.g. p=5, q=2, n=1 2<5-1 OR p=3, q=3 and n=1 in case p=q which is possible because we are not told that they cannot be equal 3>3-1, hence Not Sufficient;
st(2) q>p, obviously Not Sufficient
Combined st(1&2): this must be Sufficient, as the only condition when st(1) allows for answering this question is q>p and automatically q>n

answer Yes and choice C

A step by step approach to this please ?


Are positive integers p and q both grater than n ?

1) p-q is grater than n

2)q>p

[kevincanspain]

A step by step approach to this please ?


Are positive integers p and q both grater than n ?

1) p-q is grater than n

2)q>p

The key is to simplify:
(1) tells us that p - q > n i.e. p > q + n Since q > 0 , we can say that p > q + n > n
Thus we know that p > n, but we have no way of comparing q with n

NOT SUFF

(2) says nothing about n
NOT SUFF

(T) q > p from (2) and p > n from (1). Thus q > n as well

SUFF

[Night reader]

Hi Kevin, may I pay you to reply on my query in pm?

A step by step approach to this please ?


Are positive integers p and q both grater than n ?

1) p-q is grater than n

2)q>p

The key is to simplify:
(1) tells us that p - q > n i.e. p > q + n Since q > 0 , we can say that p > q + n > n
Thus we know that p > n, but we have no way of comparing q with n

NOT SUFF

(2) says nothing about n
NOT SUFF

(T) q > p from (2) and p > n from (1). Thus q > n as well

SUFF

[kevincanspain]

Could you resend it? Thanks