Weighted Average problem?

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by GMATGuruNY » Thu Dec 16, 2010 12:32 pm
GHong14 wrote:How to solve?
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If equal amounts of X and Y are combined (150 grams of each), the percentage of protein in the resulting mixture would be (10+15)/2 = 12.5%, resulting in .125*300 = 37.5 grams of protein. Since the mixture contains just a bit more protein (38 grams), it must include a bit more than 150 grams of Y, which contains a higher percentage of protein, and a bit less than 150 grams of X, which contains a lower percentage of protein.

The correct answer is B.

Alternatively, we could plug in the answer choices for the amount of X contained in the mixture:

Answer choice B: 140 grams X, 160 grams Y
.1*140 = 14
.15*160 = 24
14+24 = 38. Success!
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by N:Dure » Thu Dec 16, 2010 12:39 pm
x+y=300
i.e x=300-y

0.1 x + 0.15y= 38

0.1 (300-y) + 0.15y =38

30 - 0.1y + 0.15y=38
0.05y = 8
y= 160

x= 300-160 = 140