DS Percentages question

[pratyoosh]

Hello,

Can anyone explain the resolution to the below DS problem:

A manufacture produced x percent more video cameras in 1994 than in 1993 and y percent more video
cameras in 1995 than in 1994. If the manufacturer produced 1,000 video cameras in 1993, how many video
cameras did the manufacturer produce in 1995?
(1) xy=20
(2) x+y+xy/100 = 9.2

Thanks.

[clock60]

you need to find what is
1000(1+x/100)(1+y/100)=1000((100+x)/100)((100+y)/100)=1/10(100+x)(100+y)=1/10(100^2+100x+100y+xy)
(1) does not provide any useful information, we have xy=20 but no separate values for x,y
(2)
x+y+xy/100 = 9.2
100x+100y+xy=920
from initial 1/10(100^2+100x+100y+xy)
we can insert and left with 1/10(100^2+920)=1092 that is our answer
so B

[fskilnik@GMATH]

Hi there!

From the fact that V95 = 1,000*(1+y/100)*(1+x/100) (verify that), we will be able to DECIDE (or to BIFURCATE) if and only if we are able to DECIDE (or to BIFURCATE) on the expression (1+y/100)*(1+x/100) ...

(1) BIFURCATES:

> Take x = 20 and y = 1 , to realize that the value asked (in the simplified expression) is 1.01*1.20 (certainly rational)
> Take x = y = square root of 20 = sqrt(20), to realize that the same value above is (1+sqrt(20)/100)^2 , and it is easy to realize that this last expression is a positive fraction of integers (thefore rational) plus an irracional number (sqrt(5) over 25), check that, therefore an irrational result, different from the one we got before, for sure!

(2) Please note that (1+y/100)(1+x/100) = 1 + 1/100 * (x+y + xy/100) therefore this sttm DECIDES (and the value is 1+ 9.2/100).

Regards,
Fabio.

[rishab1988]

Read the problem carefully.It applies the concept of Compound Interest,in which the interest in second year and each subsequent year is calculated on the principle+interest in the previous year).

the c.i formula of p=1000 r=x for 2 years is

A(amount in 1995)= 1000(1+x/100)^2. Now if rate of interest in second year is different from rate of interest in first year,lets say y,then the formula becomes:

A= 1000(1+x/100)(1+y/100)
= 1000 [ 1+x/100+y/100+ xy/(100)^2]
= 1000 + 10x +10y +xy/10
= 1000 + 10 [x+y+xy/100]

In short the question asks : x+y+xy/100 =? or x+y=? and xy=?

1) it gives xy=20 but x+y could be anything; x=5 y=4 x+y=9 x=20 y=1 x+y=21.

Hence the amount in 1995 will be different.Not sufficient.Eliminate A and D

2) gives x+y+xy/100 =9.2

hence sufficient.

You can go ahead and solve 1000+10 [9.2]=1092

[pratyoosh]

Thank you Clock60, Fabio and Rishab.