BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

hard PS factors

Expert replies
Source: — Problem Solving |

Re: hard PS factors

by parallel_chase » Thu Sep 11, 2008 9:14 pm
jsl wrote:What is the value of b if 2x-1 is a factor of 2x^2 + bx + 3

A. -7
B. -3
C. -1
D. 3
E. 7
I have solved it using Factor theorem.
2x-1 = 0

x=1/2

2* 1/4 + b/2 +3 = 0

1/2 + 3 + b/2 = 0

7/2 + b/2 = 0

therefore, b should be -7.

Whats the OA?
Join the discussion

Re: hard PS factors

by sudhir3127 » Thu Sep 11, 2008 9:53 pm
jsl wrote:What is the value of b if 2x-1 is a factor of 2x^2 + bx + 3

A. -7
B. -3
C. -1
D. 3
E. 7

try to factor out 2x^2 + bx + 3
we know one factor is 2X-1

( 2x-1 ) ( x-3)

2X^2- 7X +3

so we know b would be -7
Join the discussion

by boysangur » Mon Nov 15, 2010 4:13 pm
parallel_chase wrote:
jsl wrote:What is the value of b if 2x-1 is a factor of 2x^2 + bx + 3

A. -7
B. -3
C. -1
D. 3
E. 7
I have solved it using Factor theorem.
2x-1 = 0

x=1/2

2* 1/4 + b/2 +3 = 0

1/2 + 3 + b/2 = 0

7/2 + b/2 = 0

therefore, b should be -7.

Whats the OA?
I'm not even familiar with factor theorem, could you explain how it fits in here? Thank you
Join the discussion

by pkan51 » Mon Nov 15, 2010 6:19 pm
sudhir3127 wrote:
jsl wrote:What is the value of b if 2x-1 is a factor of 2x^2 + bx + 3

A. -7
B. -3
C. -1
D. 3
E. 7
2X^2- 7X +3

so we know b would be -7
Should b be (7)? 2X^2-(7)X+3
Join the discussion

by Rezinka » Mon Nov 15, 2010 10:57 pm
@ boysangur :
Whenever any expression 'a' is a factor of expression 'b', you can equate expression 'a' to 0 and put the value in expression 'b' and the result would be 0.
E.g.
Say, x-1 is a factor of a*(x^2) + b*x + c
Now,
equate x - 1 to 0
i.e.
x-1=0
or, x=1
Put this value in the given expression and the result should be 0.
i.e.
Put x = 1 in a*(x^2) + b*x + c and equate to 0.
or,
a*(1^2) + b*1 + c = 0
or, a + b + c = 0
If the valus of any 2 variables are given, we can find the value of the third.

Coming to the question that is stated :
we are given
2x - 1 is a factor of 2x^2 + bx + 3

Equate 2x-1 to 0
or, 2x - 1 = 0
or, x = 1/2

Now put this valus of x in the expression;
2*{(1/2)^2)} + b*(1/2) + 3 = 0
or, 2*(1/4) + b/2 + 3 = 0
or; 1/2 + b/2 = -3
or, b = -7
Join the discussion