BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Word Problem (Overlapping Set and Volume)

Expert replies
by Cedagmat » Mon Nov 15, 2010 2:56 pm
Of the employees in a company, 30 % are female who have a master degree. If 20 % of the female employees do not have a master degree, what percent of the employees in the company are female?
(A) 25 % (B) 30 % (C) 32.5 % (D) 37.5 % (E) 45 %
[spoiler]Answer: B[/spoiler]

I can't seem to breakdown this question. It doesn't seem to have enough information.

The length, width, and height of a rectangular solid are in the ratio of 3 to 2 to 2. If the volume of the solid is V, what is the height, in terms of V?
(A) sqrt(V/3)
(B) cube rt(V/3)
(C) sqrt(2V/3)
(D) cube rt(2V/3)
(E) cube rt(4V/3)

[spoiler]Answer: D[/spoiler]
V=lwh=3*2*2
h=V/lm=V/6

What are we suppose to gather from the answer choices?
Join the discussion
Source: — Problem Solving |

by diebeatsthegmat » Mon Nov 15, 2010 5:54 pm
Cedagmat wrote:Of the employees in a company, 30 % are female who have a master degree. If 20 % of the female employees do not have a master degree, what percent of the employees in the company are female?
(A) 25 % (B) 30 % (C) 32.5 % (D) 37.5 % (E) 45 %
[spoiler]Answer: B[/spoiler]

I can't seem to breakdown this question. It doesn't seem to have enough information.

The length, width, and height of a rectangular solid are in the ratio of 3 to 2 to 2. If the volume of the solid is V, what is the height, in terms of V?
(A) sqrt(V/3)
(B) cube rt(V/3)
(C) sqrt(2V/3)
(D) cube rt(2V/3)
(E) cube rt(4V/3)

[spoiler]Answer: D[/spoiler]
V=lwh=3*2*2
h=V/lm=V/6

What are we suppose to gather from the answer choices?
there is something wrong with the question1, can you recheck? whats the solve?
Join the discussion

by Cedagmat » Mon Nov 15, 2010 7:17 pm
Sorry I do not have the solution to the problem only the answer. I was pretty stumped on this question because it seems to missing a piece of information.
Join the discussion

by goyalsau » Mon Nov 15, 2010 9:06 pm
Cedagmat wrote:Of the employees in a company, 30 % are female who have a master degree. If 20 % of the female employees do not have a master degree, what percent of the employees in the company are female?
(A) 25 % (B) 30 % (C) 32.5 % (D) 37.5 % (E) 45 %
[spoiler]Answer: B[/spoiler]
I just don't understand How the answer is B,

Just look at this example,

if there are 200 employees in a company then there are 60 female with master degree
then this 30 % female employees with master degree are 80 % of all female employees because the rest 20% of female employees do not have a master degree
which means there are 75 female employees 75/200 is 37.5%
Saurabh Goyal
[email protected]
-------------------------


EveryBody Wants to Win But Nobody wants to prepare for Win.
Join the discussion

by Rahul@gurome » Mon Nov 15, 2010 10:06 pm
Cedagmat wrote:The length, width, and height of a rectangular solid are in the ratio of 3 to 2 to 2. If the volume of the solid is V, what is the height, in terms of V?
(A) sqrt(V/3)
(B) cube rt(V/3)
(C) sqrt(2V/3)
(D) cube rt(2V/3)
(E) cube rt(4V/3)
The ratio of the length, width, and height is given. If we take them as their values, the solution becomes more conceptual. The general process to solve these kind of problems is:

Say, Length = 3x => Width = Height = 2x
Therefore, volume = (3x)*(2x)*(2x) = 12*x³

So, 12*x³ = V
= > x³ = V/12
=> x = cube rt (V/12)

Therefore, Height = 2x = 2*cube rt (V/12) = cube rt(8V/12) = cube rt(2V/3)

The correct answer is D.



Now, if we take length = 3, width = 2, and height = 2, Volume = 12

Given that, volume is V and we have to find the height. We can solve this by making V = 12 in the answer choices. The option that results in height = 2 is the correct one.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion

by Rezinka » Mon Nov 15, 2010 10:33 pm
1)
The answer id definitely D.
I found it using the table method.
No doubts there.

2)
ANS : D

This solution might look time consuming but it took me 1 minute 24 sec so I guess it is good enough.
l : w : h = 3 : 2 : 2 = 3x : 2x : 2x
Now, V = l*w*h = (3x)*(2x)*(2x) = 12(x^3)
h = v/(l*w)
= 12(x^3) / (3x*2x)
= 2x
Now we try plugging in using V=12(x^3).
We know that sqrt is the wrong option as sqrt(x^3) will not give us x and we need the ans to be 2x..
Eliminate A and C.
Lets start with the last option (cause thats what I did)
E)
cube rt(4V/3)
= cube rt(4*12(x^3/3))
= x*cube rt(16)................................. INCORRECT
D)
cube rt(2V/3)
= cube rt (2*12(x^3)/3)
= cube rt (8*(x^3))
= 2x................................................ CORRECT
Join the discussion