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Venn Diagram question

Expert replies
by bigguy_aug » Tue Nov 02, 2010 9:01 pm
I found this question in #300 Quant questions.
I do not understand the solution.

It will be great if someone can solve and explain their thought process.

Thanks

Here is the question:

At a certain school, each of the 150 students takes between 1 and 3 classes. The 3 classes available are Math, Chemistry and English. 53 students study math, 88 study chemistry and 58 study english. If 6 students take all 3 classes, how many take at least 2 classes?
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Source: — Problem Solving |

by kvcpk » Tue Nov 02, 2010 10:12 pm
Atleast 2 classes means 2 classes or 3 classes.

number of students who take 3 classes = 6
number of students who take 2 classes = X+Y+Z

P+X+Y+6 = 53
Q+X+6+Z = 88
R+Y+6+Z = 58
Adding these 3,
P+Q+R+X+Y+Z+X+Y+Z+18 = 199

But we know that
P+Q+R+X+Y+Z+6 = 150

Hence X+Y+Z+12 +150 = 199
X+Y+Z = 37

So number of students who took atleast 2 classes = 37+6=43

Hope this helps!!
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by bigguy_aug » Tue Nov 02, 2010 10:20 pm
Thanks so much for such a detailed explanation.!!
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by bigguy_aug » Tue Nov 02, 2010 10:28 pm
I agree that the "number of students who take 2 classes = X+Y+Z"

and the fact that X+Y+Z = 37

but I do not understand why u added 6 to 37. (So number of students who took atleast 2 classes = 37+6=43_
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by kvcpk » Tue Nov 02, 2010 10:54 pm
bigguy_aug wrote:I agree that the "number of students who take 2 classes = X+Y+Z"

and the fact that X+Y+Z = 37

but I do not understand why u added 6 to 37. (So number of students who took atleast 2 classes = 37+6=43_
Hi,

The question is asking for the number of students who took ATLEAST 2 courses.
Which means, it is the sum of
Number of students who took exactly 2 courses (=x+y+z = 37)
and
Number of Students who took exactly 3 courses. (= 6)

Thats the reason we get 37+6 = 43.

Hope this helps!!
"Once you start working on something,
don't be afraid of failure and don't abandon it.
People who work sincerely are the happiest."
Chanakya quotes (Indian politician, strategist and writer, 350 BC-275BC)
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by GMATGuruNY » Wed Nov 03, 2010 2:17 am
bigguy_aug wrote:I found this question in #300 Quant questions.
I do not understand the solution.

It will be great if someone can solve and explain their thought process.

Thanks

Here is the question:

At a certain school, each of the 150 students takes between 1 and 3 classes. The 3 classes available are Math, Chemistry and English. 53 students study math, 88 study chemistry and 58 study english. If 6 students take all 3 classes, how many take at least 2 classes?
Here is the formula for 3 overlapping groups in which sometimes 2 of the groups overlap and sometimes all 3 groups overlap:

T = G1 + G2 + G3 - (those in 2 of the groups) - 2*(those in all 3 groups)


The trick with overlapping group problems is to subtract the overlap. When we add together all the students who study math, all who study chemistry, and all who study English, those who study 2 subjects will be counted twice, so they need to subtracted from the total once. Those who study all 3 subjects will be counted 3 times, so they need to be subtracted from the total twice.

In the problem above:
T = 150
G1+G2+G3 = Math + Chemistry + English = 53+88+58
Students who study 2 subjects = x
Students who study all 3 subjects = 6

Plugging into the formula, we get:

150 = 53 + 88 + 58 - x - 2*6
150 = 187 - x
x = 37 students who study exactly 2 subjects.

Since 37 students study exactly 2 subjects and 6 students study all 3, 37+6 = 43 students who study at least 2 subjects.
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