x^2 + 4 y^2 = 4 x y

[sanju09]

If x^2 + 4 y^2 = 4 x y then (x + y)/ (x - y) is
(A) 2/3
(B) 2
(C) 3
(D) 10/3
(E) 4


[spoiler]???????????[/spoiler]

[shovan85]

IMO C

x^2 + 4y^2 - 4xy = 0
=> x^2 - 2 * x * 2y + (2y)^2 = 0
=> (x-2y)^2 = 0
=> x = 2y
=> x/y = 2

Apply Componendo Dividendo:

(x+y)/(x-y) = (2+1)/(2-1) = 3

FYI: https://en.wikipedia.org/wiki/Componendo_and_dividendo

[fskilnik@GMATH]

x^2 + 4y^2 - 4xy = 0
=> x^2 - 2 * x * 2y + (2y)^2 = 0
=> (x-2y)^2 = 0
=> x = 2y
=> x/y = 2

Apply Componendo Dividendo:

(x+y)/(x-y) = (2+1)/(2-1) = 3

FYI: https://en.wikipedia.org/wiki/Componendo_and_dividendo

Excellent, Shovan.

Please note that substituting x by 2y in the expression asked we find the exact same answer, for sure...

[shovan85]

x^2 + 4y^2 - 4xy = 0
=> x^2 - 2 * x * 2y + (2y)^2 = 0
=> (x-2y)^2 = 0
=> x = 2y
=> x/y = 2

Apply Componendo Dividendo:

(x+y)/(x-y) = (2+1)/(2-1) = 3

FYI: https://en.wikipedia.org/wiki/Componendo_and_dividendo

Excellent, Shovan.

Please note that substituting x by 2y in the expression asked we find the exact same answer, for sure...

Thanks. I did that for cross verification but did not post it here

[fskilnik@GMATH]

I did that for cross verification but did not post it here

Sure! I just mentioned it because someone could imagine that this (neat) tool/result you used was essential to get the answer, and of course it was not the case.

[sandeep800]

although at first look i would have tried to solve it by using componendo and dividendo but yeah substitution works well here... !!

[AtifS]

My explanation:
x^2 + 4y^2 = 4xy
=> x^2 + 4 y^2 - 4xy = 0
=> x^2 - 4 xy + 4 y^2 = 0
=> (x - 2y)^2 = 0
=> x - 2y = 0
=> x = 2y
=> x/2 = y

Now put the value of x/2 into (x + y)/(x - y)

(x + y)/(x - y)
= (x + x/2)/(x - x/2)
= {(2x+x)/2}/{(2x-x)/2}
= (3x/2)/(x/2)
= (3x/2) * (2/x)
= 3x/2 * 2/x ---> 2 will be canceled and x as well (because they are reciprocals of each other)
= 3 --> Answer
So, "C" is the answer for me, which is "3"

[bacchewar_prashant]

C for me

[frank1]

If x^2 + 4 y^2 = 4 x y then (x + y)/ (x - y) is
(A) 2/3
(B) 2
(C) 3
(D) 10/3
(E) 4


[spoiler]???????????[/spoiler]

x^2 + 4 y^2 = 4 x y
x^2 + 4 y^2 - 4 x y=0(it is in form a^2+2ab+b^2 where a=x and b=2y)
so
(x-2y)^2=0
x=2y
now actual question is x+y / x -y =?
substitute x=2y

2y+y / 2y-y =3y/y =3

So C
thanks

[pkit]

Very nice solution, thanks