Answer: E
(1) BIFURCATES:
> Take x = 20 and y = 0 , then (x +|y|)/2 = 10
> Take x = 21 and y = -1 , then (x +|y|)/2 = 11
(2) BIFURCATES, from exactly the same examples (for instance),
Therefore (1+2) also BIFURCATES, hence the answer is "E", as mentioned.
Regards,
Fábio.
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ABSOLUTE AVERAGE,MGMAT
Source: Beat The GMAT — Data Sufficiency |
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(x+|y|)/2=?
stmt1,
x+y=20
x=10,y=10,Average=10
x=30,y=-10,Average=20
Insuff
stmt2,
|x+y|=20
Either x+y=20 or x+y=-20
There are many values possible for X and Y and average varies.
Insuff
Combining 1 and 2,
x+y=20
x=10,y=10,Average=10
x=30,y=-10,Average=20
Insuff
Pick E
stmt1,
x+y=20
x=10,y=10,Average=10
x=30,y=-10,Average=20
Insuff
stmt2,
|x+y|=20
Either x+y=20 or x+y=-20
There are many values possible for X and Y and average varies.
Insuff
Combining 1 and 2,
x+y=20
x=10,y=10,Average=10
x=30,y=-10,Average=20
Insuff
Pick E
--Anand--
Can we take average of x+|y| as x+y/2 ,or x-y/2,
then,
the first stmnt says x+y=20, but no way to find out x-y.Hence, insufficient
2nd stmnt, x+y=20 , or x+y= -20. So insufficient.
Combining the 2 stmnts, we get x+y=20. We still dont know x-y. So both together also insufficient.
Hence, the answer is E.
I just wanted to confirm if this working is correct, or just coincidence that i got it right.
Thanks for such immediate replies!
then,
the first stmnt says x+y=20, but no way to find out x-y.Hence, insufficient
2nd stmnt, x+y=20 , or x+y= -20. So insufficient.
Combining the 2 stmnts, we get x+y=20. We still dont know x-y. So both together also insufficient.
Hence, the answer is E.
I just wanted to confirm if this working is correct, or just coincidence that i got it right.
Thanks for such immediate replies!
