Well I think a graph would be really good here but it is not necessary to solve the question
coz the Q says "large population has a distribution that is symmetric about the mean m."
so 68% is within 1 sd of the mean i.e m+d, m-d =68%
remainig is 32% since the distribution is symmetrical abt the mean hence this 32% would be evenly divided on both the sides of the mean i.e 16% to the right & 16 % to the left
now the 16% to the right is greater than the mean & is also greater than m+d, so this is the portion which is only greater than m+d
hence the reqd % = 100 -16 = 84%
hope this is helpful
Regards
Samir