Statement 1 is clearly insufficient. From Statement 2, we haveblaster wrote:What is x?
(1) |x| < 2
(2) |x| = 3x - 2
|x| = 3x - 2
If x were negative, then 3x - 2 would be negative, but if 3x - 2 is negative, it can't possibly be equal to |x|. So x must be greater than or equal to zero, in which case |x| = x. So we can rewrite our equation as x = 3x - 2, and we can solve for x (we find that x = 1). So the answer is B.
