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by selango » Mon Oct 04, 2010 4:38 am
Length of arc ABC=2/3 *(Circumference of circle)

24=2/3*(2*Pi*r)=2/3(pi*d)

pi*d=36 or d=36/pi=11

Pick C
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by girishbtg » Mon Oct 04, 2010 4:47 am
selango wrote:Length of arc ABC=2/3 *(Circumference of circle)

24=2/3*(2*Pi*r)=2/3(pi*d)

pi*d=36 or d=36/pi=11

Pick C

but how you can take this statement ->


Length of arc ABC=2/3 *(Circumference of circle) .....? why
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by Rahul@gurome » Mon Oct 04, 2010 7:10 am
Angle inscribed by arc AC at the center of circle is twice the angle inscribed at any other point in the circle. So, angle inscribed by arc AC at the center of the circle = 2(60) = 120º
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Length of arc ABC = (240/360)*2(pi)(radius) = (2/3)*2(pi)*(r) = 24
We need to find the value of 2(r)
So, 2r = (24 * 3)/(2)*(pi) = 36/(pi) = 11 (appr.)

The correct answer is [spoiler](C)[/spoiler].
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by pzazz12 » Tue Oct 05, 2010 3:51 am
Rahul@gurome wrote:Angle inscribed by arc AC at the center of circle is twice the angle inscribed at any other point in the circle. So, angle inscribed by arc AC at the center of the circle = 2(60) = 120º
Image
Length of arc ABC = (240/360)*2(pi)(radius) = (2/3)*2(pi)*(r) = 24
We need to find the value of 2(r)
So, 2r = (24 * 3)/(2)*(pi) = 36/(pi) = 11 (appr.)

The correct answer is [spoiler](C)[/spoiler].
thank you,but can you explain me little bit clear...
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by Rahul@gurome » Tue Oct 05, 2010 3:57 am
pzazz12 wrote: thank you,but can you explain me little bit clear...
Angle inscribed by arc ABC at the center of circle = 240º (as explained earlier)
Angle at the center of the circle = 360º
Therefore, length of arc ABC = (240/360)*2(pi)(radius)

Hope that helps.
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