BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

average weight

Expert replies
by alivapriyada » Wed Sep 29, 2010 11:03 pm
What is the average weight of the class?
A. The ratio of the average weight of all the boys and girls is 3:2
B. The number of boys and girls in the class are 40 and 60 respectively

[spoiler]OA later
[/spoiler]
Join the discussion
Source: — Data Sufficiency |

by ashokkadam » Thu Sep 30, 2010 12:08 am
alivapriyada wrote:What is the average weight of the class?
A. The ratio of the average weight of all the boys and girls is 3:2
B. The number of boys and girls in the class are 40 and 60 respectively

[spoiler]OA later
[/spoiler]
Statement 1 is insufficient, so we are left with B,C,E
Statement 2 is insufficient, so we are left with C,E

Together, sufficient so answer is C.

This is a question on Weighted averages.
Force and mind are opposites; morality ends where a gun begins.
Join the discussion

by alivapriyada » Thu Sep 30, 2010 2:23 am
ashokkadam wrote:
alivapriyada wrote:What is the average weight of the class?
A. The ratio of the average weight of all the boys and girls is 3:2
B. The number of boys and girls in the class are 40 and 60 respectively

[spoiler]OA later
[/spoiler]
Statement 1 is insufficient, so we are left with B,C,E
Statement 2 is insufficient, so we are left with C,E

Together, sufficient so answer is C.

This is a question on Weighted averages.
i dont think that C will work.could you plz explain it a bit more??
Will give the OA soon.
Join the discussion

by ashokkadam » Thu Sep 30, 2010 2:36 am
Average weight of the class = (Total weight of boys + Total weight of girls) / (Total number of boys + Total number of girls)

Since we cannot calculate the total weight, E has to be the answer.......hehehe ;)
alivapriyada wrote:
ashokkadam wrote:
alivapriyada wrote:What is the average weight of the class?
A. The ratio of the average weight of all the boys and girls is 3:2
B. The number of boys and girls in the class are 40 and 60 respectively

[spoiler]OA later
[/spoiler]
Statement 1 is insufficient, so we are left with B,C,E
Statement 2 is insufficient, so we are left with C,E

Together, sufficient so answer is C.

This is a question on Weighted averages.
i dont think that C will work.could you plz explain it a bit more??
Will give the OA soon.
Force and mind are opposites; morality ends where a gun begins.
Join the discussion

by alivapriyada » Thu Sep 30, 2010 2:57 am
ashokkadam wrote:Average weight of the class = (Total weight of boys + Total weight of girls) / (Total number of boys + Total number of girls)

Since we cannot calculate the total weight, E has to be the answer.......hehehe ;)
alivapriyada wrote:
ashokkadam wrote:
alivapriyada wrote:What is the average weight of the class?
A. The ratio of the average weight of all the boys and girls is 3:2
B. The number of boys and girls in the class are 40 and 60 respectively

[spoiler]OA later
[/spoiler]
Statement 1 is insufficient, so we are left with B,C,E
Statement 2 is insufficient, so we are left with C,E

Together, sufficient so answer is C.

This is a question on Weighted averages.
i dont think that C will work.could you plz explain it a bit more??
Will give the OA soon.
lets wait for some more options.
Join the discussion

by monusangeeta » Thu Sep 30, 2010 10:45 pm
Hi,

My answer is also E. My approach was:

Statement 2: Totall Insuf, says nothing about weights
Statement 1: Insuf, Avg B: Avg G = 3:2 => Actual Avg B and G = 3x, 2x, Still we dont know no. of Girls and boys

Combining both, Statment 1 needs 3 variables: x, no. of boys and no. of girls, Statement 2 provides values for 2 variables: no. of boys and no. of girls. however, value of variable x is still missing. For diff value of x, there will be diff value of avg weight of the class. Insuff.

E wins.

Thanks
monusangeeta
Join the discussion

by kvcpk » Thu Sep 30, 2010 11:40 pm
alivapriyada wrote:What is the average weight of the class?
A. The ratio of the average weight of all the boys and girls is 3:2
B. The number of boys and girls in the class are 40 and 60 respectively

[spoiler]OA later
[/spoiler]
Average weight = total weight of class/ strength of class

A. The ratio of the average weight of all the boys and girls is 3:2
avg weight of boys = total wt of boys/number of boys = TWB/NB
similarly avg wt of girls = TWG/NG
We are given that TWB/NB * (NG/TWG) = 3/2
We do not know any particualr value to proceed further. hence INSUFF

B. The number of boys and girls in the class are 40 and 60 respectively
INSUFF because it doesnt speak about weights at all.

Combining:
NB = 40
NG = 60
Hence from stmt1,
TWB/40 * 60/TWG = 3/2
Hence, TWB = TWG
Total weight of class = TWB+TWG
Strength of class = 6+40 = 100
Hence avg = 2(TWB)/100 = TWB/50

Still we do not know TWB or TWG or TWC

Hence INSUFF

pick E.
"Once you start working on something,
don't be afraid of failure and don't abandon it.
People who work sincerely are the happiest."
Chanakya quotes (Indian politician, strategist and writer, 350 BC-275BC)
Join the discussion

by alivapriyada » Thu Sep 30, 2010 11:45 pm
OA E. kudos to all!!!
Join the discussion

by sumit.sinha » Fri Oct 01, 2010 5:33 am
alivapriyada wrote:What is the average weight of the class?
A. The ratio of the average weight of all the boys and girls is 3:2
B. The number of boys and girls in the class are 40 and 60 respectively

[spoiler]OA later
[/spoiler]
What is Total Weight/ Total students?
OR (Total weight Boys + total Weight Girls)/ (total boys + total girls)
i.e ( Tb+Tg)/(b+g)? ------------------(1)

(1) Ab/Ag = 3/2
(Tb*g)/(Tg*b) = 3/2
Substituting in (1)
3/2 (Tg)
Since we don't know weight of total girls (or boys for that instance). Insufficient

(2) b= 40, g = 60
Insufficient

(1) and (2) together
as b+g cancel each other out in Statement (1), knowing the number of boys and girls are still not sufficient, we need to know the total weight of girls or boys.

Pick E.
Cheers,
Sumit
Join the discussion

by GMATGuruNY » Fri Oct 01, 2010 9:03 am
alivapriyada wrote:What is the average weight of the class?
A. The ratio of the average weight of all the boys and girls is 3:2
B. The number of boys and girls in the class are 40 and 60 respectively

[spoiler]OA later
[/spoiler]
The easiest -- and perhaps safest -- approach is to plug in twice.

Statements 1 and 2 together:
Plug in that each boy weighs 3 pounds, each girl 2 pounds.
Total weight of boys = 40*3 = 120
Total weight of girls = 60*2 = 120
Average = 240/100 = 2.4

Plug in that each boy weighs 6 pounds, each girl 4 pounds.
Total weight of boys = 40*6 = 240
Total weight of girls = 60*4 = 240
Average = 480/100 = 4.8

Since the average can be 2.4 or 4.8, insufficient.

The correct answer is E.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by goyalsau » Sat Oct 02, 2010 3:08 pm
alivapriyada wrote:What is the average weight of the class?
A. The ratio of the average weight of all the boys and girls is 3:2
B. The number of boys and girls in the class are 40 and 60 respectively

[spoiler]OA later
[/spoiler]
I would like to add just one thing.
we are looking for average weight and no weight is given so should be E,
Saurabh Goyal
[email protected]
-------------------------


EveryBody Wants to Win But Nobody wants to prepare for Win.
Join the discussion