sum of integers in 2 different sets is equal...

[cooperbaker]

The sum of the integers in list S is the same as the sum of integers in list T. Does S contain more integers than T?

(1) The average (arithmetic mean) of the integers in S is less than the average of the integers in T

(2) The median of the integers in S is greater than the median of the integers in T

The OA is B, but i'm confused as to why...

It doesn't say only positive integers, so couldn't you theoretically add a negative number (and its absolute value) to not change the average, but add two more integers?

[peddisetty]

Since their sum is same. Avg is inversely proportional to no of integers. So if the no of integers are more, avg would be less. By this we can say which one has more no of integers.

Thanks,
Raj Peddisetty.

[sjd00d]

shouldn't the answer be A?

[cooperbaker]

shouldn't the answer be A?

Sorry, yes A is correct!

[monusangeeta]

Dear Experts,

I am restarting this thread as I don't understand the solution fully and need your help.

The sum of the integers in list S is the same as the sum of the integers in list T. Does S contain more integers than T?

1) The average (arithmetic mean) of the integers in S is less than the average of the integers in T.

2) The median of the integers in S is greater than the median of the integers in T.

My approach is:

Statement 1: Avg of S< Avg of T

Lets take data: S = 1,2, 3, 4 avg is 2.5, sum is 10, T = 4, 6 Sum is 10, avg is 5 => S>T - Not sufficient

Statement 2: I am not sure how to approach to statement 2.


I will post the answer subsequently.

Many thanks.

[clock60]

hi guys
recently i struggled with the same problem, but did not obtain oa. i see now that my answer is correct, for those who are interested follow below link
https://www.beatthegmat.com/integer-t67285.html