Inequalities: If x is a positive integer, is x<1 ?

[II]

If x is a positive integer, is X<1 ?

(1) 2x < 1
(2) 2x <= 2

(A) Statement (I) ALONE is sufficient, but statement (II) alone is not sufficient
(B) Statement (II) ALONE is sufficient, but statement (I) is not sufficient
(C) BOTH statements TOGETHER are sufficient, but NEITHER statement alone is sufficient
(D) Each statement ALONE is sufficient
(E) Statements (I) and (II) TOGETHER are NOT sufficient

Can you please let me know how you come to the answer ?
Thanks in advance.
II

[StarDust845]

Is the answer B ?

[II]

Is the answer B ?

How did you come to that answer ?
And no ... answer is not A.

[sujaysolanki]

From 1 we get X < 0.5 so X definitely less < 1 Hence sufficient

From 2 x could be =1 or less than 1 Hence Insufficient

Hence A

[camitava]

If x is a positive integer, is X<1 ?

(1) 2x < 1
(2) 2x <= 2

In the Qs, it is saying that X is a positive number and according to the conclusion X < 1. So X has to be 0 only.
Now by 1, X <1> Which proves X < 1
But by 2, 2X <2> X <1> Which is saying that X can be equal to 1 or less than 1. So no direct conclusion you can draw.
So IMO A.

[StarDust845]

I disagree with sujaysolanki's and camitava's solution.

In the stem it states that x is a positive integer (0 is not). That means x is 1,2,3 etc.

From (1) I know that x < 0.5, but is there a solution to this inequality given the stem? NO. If there is no solution how can you say that it proves X < 1?????

But from (2) I know x <= 1 and from stem x can't be 0 (0 is not a positive integer) hence x must be 1 and hence the answer is B.

What's the official answer?

Thanks,
Calista.