function

[magical cook]

if f is the function defined for all k by f(k)=k^5/16, what is f(2k) in terms of f(k)?

a. 1/8 f(k)
b. 5/8 f(k)
c. 2 f(k)
d. 10 f(k)
e. 32 f(k)

[gmatguy16]

imo e f(2k)= (2k) ^ 5 / 16 = 32 k ^5/16 = 32 f(k)

[camitava]

Agree with gmayguy16. IMO E too.

[magical cook]

that's the answer - thank you!

[andes1]

imo e f(2k)= (2k) ^ 5 / 16 = 32 k ^5/16 = 32 f(k)

i was lost

i tried this:
(2k)^(5/16)

then
{(2^5)(k^5)}^(1/16)
next:
[32k^5]^(1/16)

so i did it until here.... was i doing something wrong?

[camitava]

andes1,
U r getting wrong man! The Qs is saying - f(2k)= (2k) ^ 5 / 16 means f(2k)= ((2k) ^ 5) / 16, I think now u can get the idea where u misunderstood the Qs!

[andes1]

andes1,
U r getting wrong man! The Qs is saying - f(2k)= (2k) ^ 5 / 16 means f(2k)= ((2k) ^ 5) / 16, I think now u can get the idea where u misunderstood the Qs!

haha thanks a lot... was a silly error from my part.