mgmat-sc-30

[pradeepkaushal9518]

A certain panel is to be composed of exactly three women and exactly two men, chosen from x women and y men. How many different panels can be formed with these constraints?

(1) If two more women were available for selection, exactly 56 different groups of three women could be selected.

(2) x = y + 1

[Rahul@gurome]

(1) Two more women were available for selection implies now number of women = x + 2
So, (x+2)C3 = 56. We can solve x from here, but no information about men is given.
So, (1) is NOT SUFFICIENT.

(2) x = y + 1 is the relationship between x and y, which clearly NOT SUFFICIENT.

Combining (1) and (2), x can be found from (1) and using (2) we can find y. So, combining the statements we can answer the question. Since this is a DS question, so no need to find the values.

The correct answer is[spoiler] (C)[/spoiler].