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by radhika1306 » Wed Dec 12, 2007 3:08 pm
If x &#8800; 0, is x^2/|x| < 1?
(1) x <1> &#8722;1
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
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Source: — Data Sufficiency |

by Suyog » Wed Dec 12, 2007 3:40 pm
Can you post option 2 again....its missing and kindly recheck option 1 too.
Thanks!
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by radhika1306 » Thu Dec 13, 2007 6:22 am
Sorry about that
(1) x <1
(2) x > &#8722;1
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by TSonam » Thu Dec 13, 2007 7:53 am
Answer is C

stmt 1: x < 1: x between 1 and -1 gives X^2/|x| < 1, but for x <1>-1: x between -1 and 1 gives x^2|x| <1> 1, it gives the opposite answer.

combining 1 and 2, we know that x is between 1 and -1, so c is the answer.
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