kmittal82 wrote:Good question
Lets say the questions are a b c d e
case 1:
You select a and b, and 2 out of c d e
Total number of ways of selecting 2 out of cde = 3c2 = 3
Total number of ways of answering questions in this = 3 x 3 x 4 x 4 x 4 x 3 = 432
The 3 is in bold because that's the possible combinations of picking 2 questions out of c d and e
case 2:
You select c d e, and 1 out of a or b
Total number of ways of answering = 4 x 4 x 4 x 3 x 2 = 384
The 2 is in bold because that's the possible combinations of picking 1 question from a and b
Thus, total ways = case1 + case 2 = 432 + 384 = 816
There was a small typo in your answer. For case 1, the the result is = 3 x 3 x 4 x 4 x
3
I was thinking in a totally different way. I was selecting 4 questions out of five and then finding the number of ways for each.Didn't work out that way.
