If -1/2<=x<=-1/3 and -1/4<=y<=-1/5 what is the minimum value of xy^2?
A -1/75
B -1/50
C -1/78
D -1/32
E -1/16
A -1/75
B -1/50
C -1/78
D -1/32
E -1/16
I think the ans is D =1/32
xy^2 = -1/2*-1/4^2 = -1/32
Whats the OA?
