Work Question

[kellyeroses]

I searched for this one before I posted but didn't find it.

Working alone at its own constant rate, a machine seals k cartons in 8 hours, and working alone at its own constant rate, a second machine seals k cartons in 4 hours. If the two machines, each working at its own constant rate and for the same period of time, together sealed a certain number of cartons, what percent of the cartons were sealed b the machine working at the faster rate?

The answer is 66 2/3% but how do I get it?

[aimhigh715]

The way I looked at it, especially when its asking for a simplistic calculation / proportion is just compare the rates.

Make sure you're basing it on the same denominators (LCD) would be helpful.

1/4 + 1/8 = 4/16 + 2/16

Faster machine is 4 : 2 in terms of speed.

4/6 is 2/3 which is ~ 66.67%

hope that helps!