1 - insuf.ri2007 wrote:If the integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of a^n what is the value of a
1) a^n = 64
2) n = 6
2^6, 4^3, 8^2 all of them yield a value of 64
2 - suf.
8! = x * a^6
Breaking down 8! into its factors,
2*3*4*5*6*7*8 = 2^7 * 3^2 * 5 * 7
'a' has to be 2
Hence B
