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Greatest value?

Expert replies
by bhumika.k.shah » Tue Mar 30, 2010 9:22 am
Which of the following fractions has the greatest value?


A.3 / 8!

B.6*(4!) / 5*(9!)

C.4*(3!) / 9!

D.3 / 5*(7!)

E.14 / 5*(8!)

Quicker and new approaches required.

Source : MGMAT QBANK
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Source: — Problem Solving |

by harshavardhanc » Tue Mar 30, 2010 9:26 am
bhumika.k.shah wrote:Which of the following fractions has the greatest value?


A.3 / 8!

B.6*(4!) / 5*(9!)

C.4*(3!) / 9!

D.3 / 5*(7!)

E.14 / 5*(8!)

Quicker and new approaches required.

Source : MGMAT QBANK
make all the denominators same ( make them 9!) and then compare the fractions.
Regards,
Harsha
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by gmatmachoman » Tue Mar 30, 2010 12:18 pm
bhumika.k.shah wrote:Which of the following fractions has the greatest value?


A.3 / 8!

B.6*(4!) / 5*(9!)

C.4*(3!) / 9!

D.3 / 5*(7!)

E.14 / 5*(8!)

Quicker and new approaches required.

Source : MGMAT QBANK
IS it B?
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by bhumika.k.shah » Tue Mar 30, 2010 12:20 pm
gmatmachoman wrote:
IS it B?
Nopes
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by bhumika.k.shah » Tue Mar 30, 2010 12:38 pm
[spoiler]OA D

Each fraction's denominator contains a factorial. Since any smaller factorial divides any larger factorial, any of the factorials smaller than 9! can be multiplied by appropriate terms. (For instance, multiplying 7! by yields 9!.) Therefore, the common denominator of all the fractions is 5(9!).

In (A) the numerator and denominator must be multiplied by 5 × 9; in (C), by 5; in (D), by 8 × 9; and in (E), by 9. No multiplication is necessary in (B).

The fractions now look like this:

(A)
3 × 9 × 5 / 5(9!)

=135 / 5(9!)

(B)
6 × 4 × 3 × 2 × 1/ 5(9!)

= 144 / 5(9!)

(C)
4 × 3 × 2 × 1 × 5/ 5(9!)

= 120/ 5(9!)

(D) 3 × 8 × 9/ 5(9!)

= 216 /5(9!)

(E) 14 × 9 / 5(9!)

= 126 / 5(9!)

Now that the denominators are all the same, we can directly compare the numerators. 216 is the largest numerator.

The correct answer is D.[/spoiler]
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by gmatmachoman » Tue Mar 30, 2010 12:43 pm
bhumika.k.shah wrote:[spoiler]OA D

Each fraction's denominator contains a factorial. Since any smaller factorial divides any larger factorial, any of the factorials smaller than 9! can be multiplied by appropriate terms. (For instance, multiplying 7! by yields 9!.) Therefore, the common denominator of all the fractions is 5(9!).

In (A) the numerator and denominator must be multiplied by 5 × 9; in (C), by 5; in (D), by 8 × 9; and in (E), by 9. No multiplication is necessary in (B).

The fractions now look like this:

(A)
3 × 9 × 5 / 5(9!)

=135 / 5(9!)

(B)
6 × 4 × 3 × 2 × 1/ 5(9!)

= 144 / 5(9!)

(C)
4 × 3 × 2 × 1 × 5/ 5(9!)

= 120/ 5(9!)

(D) 3 × 8 × 9/ 5(9!)

= 216 /5(9!)

(E) 14 × 9 / 5(9!)

= 126 / 5(9!)

Now that the denominators are all the same, we can directly compare the numerators. 216 is the largest numerator.

The correct answer is D.[/spoiler]
I tried this whole problme in my mind.. It was confusing ....!!
Sorry Bhumika for bugging u like anything!!

But atlast I got D!!
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by harshavardhanc » Tue Mar 30, 2010 12:47 pm
harshavardhanc wrote:
bhumika.k.shah wrote:Which of the following fractions has the greatest value?


A.3 / 8!

B.6*(4!) / 5*(9!)

C.4*(3!) / 9!

D.3 / 5*(7!)

E.14 / 5*(8!)

Quicker and new approaches required.

Source : MGMAT QBANK
make all the denominators same ( make them 9!) and then compare the fractions.
so, we have to compare

3*9 , (6*24)/5 , (4*6) , (3*8*9)/5 , and (14*9)/5

or 27, 24, (6*24)/5, (3*8*9)/5 , and (14*9)/5

first compare : (6*24)/5, (3*8*9)/5 , and (14*9)/5

= (24*6)/5, (24*9)/5 , and (14*9)/5

The middle one :(24*9)/5 is greatest.


Now decide : which one is greater (24*9)/5 or 27 ? Or (9* 4.something) or (9*3) ? :)


hence, Ans : D
Regards,
Harsha
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by gmatmachoman » Wed Mar 31, 2010 2:26 am
@Harsha Bhai,
Can u try this prblm without using pen/Paper.. & that too in 1 min??
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by harshavardhanc » Wed Mar 31, 2010 2:40 am
gmatmachoman wrote:@Harsha Bhai,
Can u try this prblm without using pen/Paper.. & that too in 1 min??
certainly not !

Buddy, to tell you I only think on paper because whenever i have tried to solve questions in my mind, I've always got an incorrect answer. I'm really a "slow head" :)
Regards,
Harsha
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by sanju09 » Wed Mar 31, 2010 2:41 am
gmatmachoman wrote:@Harsha Bhai,
Can u try this prblm without using pen/Paper.. & that too in 1 min??
we'll do the circus later, for now the problem is fixed in no more than the ideal 2 minutes
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
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by sanju09 » Wed Mar 31, 2010 2:45 am
harshavardhanc wrote:
gmatmachoman wrote:@Harsha Bhai,
Can u try this prblm without using pen/Paper.. & that too in 1 min??
certainly not !

Buddy, to tell you I only think on paper because whenever i have tried to solve questions in my mind, I've always got an incorrect answer. I'm really a "slow head" :)
Same here, I have in point of fact divided my brain in two parts, LEFT and RIGHT. In the LEFT part, there's nothing RIGHT, and in the RIGHT part, there's nothing LEFT
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion

by harshavardhanc » Wed Mar 31, 2010 2:50 am
sanju09 wrote:
Same here, I have in point of fact divided my brain in two parts, LEFT and RIGHT. In the LEFT part, there's nothing RIGHT, and in the RIGHT part, there's nothing LEFT
ROFL
Last edited by harshavardhanc on Wed Mar 31, 2010 2:53 am, edited 1 time in total.
Regards,
Harsha
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by sanju09 » Wed Mar 31, 2010 2:52 am
harshavardhanc wrote:
sanju09 wrote:
harshavardhanc wrote:
gmatmachoman wrote:@Harsha Bhai,
Can u try this prblm
Same here, I have in point of fact divided my brain in two parts, LEFT and RIGHT. In the LEFT part, there's nothing RIGHT, and in the RIGHT part, there's nothing LEFT
ROFL
congrats Govind, we're 3 now
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion

by kstv » Wed Mar 31, 2010 5:29 am
A.3 / 8! B.6*(4!) / 5*(9!) C.4*(3!) / 9! D.3 / 5*(7!) E.14 / 5*(8!)
Since the job is to find the max value compairing will yield the result with minimum calculation.
A and E both have 8! in the denominator (D) multiply by 5 the numerator (N) of A will be 15 , N of E = 14
B and C both have 9! in the denominator (D) multiply by 5 the N of B = 6! and C 5!
A 15/8! and B 6!/9! D 15/7! obvious that D is > A as (N) is the same
between B and D - am still doing it mentally.
Last edited by kstv on Wed Mar 31, 2010 5:55 am, edited 1 time in total.
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by sanju09 » Wed Mar 31, 2010 5:48 am
kstv wrote:A.3 / 8! B.6*(4!) / 5*(9!) C.4*(3!) / 9! D.3 / 5*(7!) E.14 / 5*(8!)
Since the job is to find the max value compairing will yield thhe result with minimum calculation.
A and E both have 8! in the denominator (D) multiply by 5 the numerator (N) of A will be 15 , N of B = 14
B and C both have 9! in the denominator (D) multiply by 5 the N of B = 6! and C 5!
A 15/8! and B 6!/9! D 15/7! obvious that D is > A as (N) is the same
between B and D - am still doing it mentally.
but, we've caught you typing some great sense here, rock u
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion