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by tsmith93 » Fri Mar 26, 2010 5:38 am
Three identical balls fit snugly into a cylindrical can: the radius of the spheres equals the radius of the can, and the balls just touch the bottom and the top of the can. If the formula for the volume of a sphere is V=4/3(pi)r^3, what fraction of the volume of the can is taken up by the balls?
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by eaakbari » Fri Mar 26, 2010 5:53 am
Volume of one sphere = 4/3 *pi*r^3
Volume of 3 spheres is = 4 *pi*r^3
Volume of cylinder is pi*r^2 h
Here h is 6 r as balls fit snugly into cylinder

Therefore vol of 3 spheres / vol of cylinder = 4/6 = 2/3


Answer = [spoiler]2/3[/spoiler]
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by sakali » Fri Mar 26, 2010 2:33 pm
I set r=1 and performed the same calculations...I got the same answer.

Answer = 2/3
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