BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

ps question 2

Expert replies
by magical cook » Sat Oct 13, 2007 9:47 am
In a room filled with 7 people, 4 people have exactly 1 friend in the room and 3 people have exactly 2 friends in the room (Assuming that friendship is a mutual relationship, i.e. if John is Peter's friend, Peter is John's friend). If two individuals are selected from the room at random, what is the probability that those two individuals are NOT friends?
Join the discussion
Source: — Problem Solving |

by Suyog » Sat Oct 13, 2007 10:44 pm
can you post the options?
Join the discussion

by samirpandeyit62 » Mon Oct 15, 2007 8:30 am
2 people can be selected out of 7 in 7c2 = 21 ways

now 4 people have exactly one friend i.e. they will constitute 2 combinations e.g AB CD (mutually 4 people with 1 friend each)

& 3 with two friends will make 3 combinations i.e EF FH HE

total =5 combinations

so probability that both are friends is 5/21

so P (both are not friends ) =1-5/21 = 16/21
Regards
Samir
Join the discussion