Functions

[arocks]

If f(x) = x-x^2 is f(a)<f(b)?

1). a<b
2). a^2< b^2

OA - E

[Suyog]

1) a < b

let a = 2 and b = 3
f(a) = 2-4 = -2
f(b) = 3-9 = -6
Therefore f(a) > f(b)

let a = -2 and b = 3
f(a) = -2(4) = -8
f(b) = 3-9 = -6
Therefore f(a) < f(b)
INSUFF

2) a^2< b^2
We can always take a positive root of a and negative root of b and vice-versa, so 2 will never be SUFF

Both statements together also dont make any difference.

Ans E.