Burger King

[GMATSUCKER]

Q: At Burger King , burgers can be bought in quantities of either 6 , 9 or 20 only . For example, one can purchase
26 (20 + 6) , 15 ( 6 + 9 ) and 24 ( 9*2 + 6) etc ,but can't purchase 10 burgers i.e without any lot. What is the largest number of burgers that can NOT be purchased ?

a)13

b)27

c)37

d)83

e)None of these

[harsh001]

83 = (4*20 + 3) - Does not satisfy condition
83 = (9*9 + 1) - Does not satisfy condition
83 = (6*13 + 5) - Does not satisfy condition

Thus in my view 83 is the answer

[thephoenix]

83 = (4*20 + 3) - Does not satisfy condition
83 = (9*9 + 1) - Does not satisfy condition
83 = (6*13 + 5) - Does not satisfy condition

Thus in my view 83 is the answer

9*7=63+20=83

[Phirozz]

Q: At Burger King , burgers can be bought in quantities of either 6 , 9 or 20 only . For example, one can purchase
26 (20 + 6) , 15 ( 6 + 9 ) and 24 ( 9*2 + 6) etc ,but can't purchase 10 burgers i.e without any lot. What is the largest number of burgers that can NOT be purchased ?

a)13

b)27

c)37

d)83

e)None of these

83 = 9*7+20
though 37 cannot be purchased its not the answer because even 40 which is greater than 37 cannot be purchased.
So answer is E(none of these)
only way to solve is thru options

[thephoenix]

Q: At Burger King , burgers can be bought in quantities of either 6 , 9 or 20 only . For example, one can purchase
26 (20 + 6) , 15 ( 6 + 9 ) and 24 ( 9*2 + 6) etc ,but can't purchase 10 burgers i.e without any lot. What is the largest number of burgers that can NOT be purchased ?

a)13

b)27

c)37

d)83

e)None of these

83 = 9*7+20
though 37 cannot be purchased its not the answer because even 40 which is greater than 37 cannot be purchased.
So answer is E(none of these)
only way to solve is thru options

40 can be purchase in 20*2=40

[Phirozz]

Q: At Burger King , burgers can be bought in quantities of either 6 , 9 or 20 only . For example, one can purchase
26 (20 + 6) , 15 ( 6 + 9 ) and 24 ( 9*2 + 6) etc ,but can't purchase 10 burgers i.e without any lot. What is the largest number of burgers that can NOT be purchased ?

a)13

b)27

c)37

d)83

e)None of these

83 = 9*7+20
though 37 cannot be purchased its not the answer because even 40 which is greater than 37 cannot be purchased.
So answer is E(none of these)
only way to solve is thru options

40 can be purchase in 20*2=40

ohh silly mistakes thanx bro
anyway 43 cannot be purchased so ans remain same as E

[GMATSUCKER]

OAE. I don't have an explanation to this problem , so I made a guess that there are other possible combinations greater than the given options that cannot be purchased. But I would like to have other people's explanations for the answer E.

[STEVEN SPIELBERG]

OAE. I don't have an explanation to this problem , so I made a guess that there are other possible combinations greater than the given options that cannot be purchased. But I would like to have other people's explanations for the answer E.

What could be the other possible explanations ? I am curious ?

[Aman verma]

What could be the other possible explanations ? I am curious ?

Yes, I would also like to know, whether there could be any other possible explanation ?